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2 years ago

Which symbol correctly compares the fractions below? 1/8 ? 1/2

Mathematics

1 answer:

antoniya [11.8K]2 years ago

6 0

Answer:

Step-by-step explanation:

1/2 = 4/8

=> 1/8 < 4/8

=> 1/8 < 1/2

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“Donations to an annual fundraiser are 15% greater this year then last year. Last year, donations were 10% greater than a year b

nexus9112 [7]

Answer: Amount was raised 2 years ago was $8000.

Step-by-step explanation:

Since we have given that

Amount raised this year = $10120

According to question,

Donation were 10% greater than a year before .

Donation were 15% greater that year than its previous year i.e. 2 years ago.

Let amount raised 2 years ago be x

So, it becomes,

$x\times \frac{115}{100}\times \frac{110}{100}=\$10120\\\\x=10120\times \frac{100}{115}\times \frac{100}{110}\\\\x=\$8000$

Hence, Amount was raised 2 years ago was $8000.

7 0

3 years ago

Read 2 more answers

Find the original price.<br> A bracelet costs $36 after a 25% discount.

kvasek [131]

Answer

$27

Step-by-step explanation:

36/4=9, 9x3=27

6 0

3 years ago

Read 2 more answers

Find the measures of the angles of each triangle (in degrees) and classify the triangle as acute/right/obtuse and scalene/isosce

stiks02 [169]

Step-by-step explanation:

given :

A=5x - 10

B = 3x

C= 2x - 10

solution:

A+B+C = 180°

5x - 10 + 3x+ 2x - 10 = 180

10x -20 = 180

10x = 200

x = 20

A = 5(20)-10 = 100-10 = 90°

B = 3x = 3(20) = 60°

C = 2x-10 =2(20)-10 =40-10 = 30°

this is the right triangle and scalene triangle

8 0

2 years ago

4y³-2(2y-3)+y written in standard form

Lady_Fox [76]

Mutiply the bracket by -2

(-2)(2y)=-4y

(-2)(-3)= 6

4y^3-4y+6+y

4y^3-4y+y+6 ( combine like terms)

4y^ 3-3y+6

Answer: 4y^ 3-3y+6

5 0

3 years ago

Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B

Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,

B = event that the selected student has a MasterCard,

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0

2 years ago