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Flura [38]
3 years ago
7

Please help me with this

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:  -6, -3, -2, -1, 1, 2, 3, 6

<u>Step-by-step explanation:</u>

NOTES: p is the last term, q is the coefficient of the first term

Determine all of the factors of p and all of the factors of q

Possible rational roots are all of the combinations of p/q for every factor

\dfrac{p}{q}=\pm \dfrac{6}{1}=\pm \dfrac{1\times 6, 2\times 3}{1}=\pm\dfrac{1}{1}, \pm\dfrac{6}{1}, \pm\dfrac{2}{1}, \pm\dfrac{3}{1}\\\\\\\text{In order from smallest to largest:}\ \large\boxed{-6, -3, -2, -1, +1, +2, +3, +6}

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