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3 years ago

a transformation of a rectangle ABCD results in rectangle ABCD whch transformation maps the pre-image to the image

Mathematics

1 answer:

hoa [83]3 years ago

3 0

Answer:

dilation

Step-by-step explanation:

did it on edge 2020

Pls make me brainliest much appreciated

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Perform the indicated matrix row operation and write the new matrix

Ne4ueva [31]

The given operation involves just swapping the two rows, so carrying out $R_1\leftrightarrow R_2$ on the matrix gives

$\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]$

5 0

3 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

1 year ago

Read 2 more answers

Can someone please help me

Kaylis [27]

9514 1404 393

Answer:

125 in²
676 km²
20 square units

Step-by-step explanation:

The Pythagorean theorem tells you the square on the hypotenuse is equal to the sum of the squares on the other two sides. (This is the version you use for problem 2.)

This also means the square on one side is the difference between the square on the hypotenuse and the square on the other side. (Use this version for problems 1 and 3.)

1. ? = 200 in² -75 in² = 125 in²

2. ? = 576 km² + 100 km² = 676 km²

3. ? = 36 square units - 16 square units = 20 square units

4 0

3 years ago

How do I answer this question

Gnom [1K]

First you have to make it multiplication so you flip 5/2 around and the two “2’s” will cancel each other so it will be 17/5 or 3 2/5

6 0

3 years ago

CAN ANYONE TELL ME WHAT THE ANWSER IS:

Anna71 [15]

2.8 I got that same on on khan academy it’s 2.8 trust me

7 0

2 years ago