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3 years ago

3x+5 = -7. i dont know to solve this please help

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

Answer: -4

Step-by-step explanation: 7-5=-12, and -12/4 is -3

notka56 [123]3 years ago

6 0

Add 5 to both sides
3x = -2
Divide 3
X = -2/3

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What does a b and c mean in algebra 1

wolverine [178]

They are variables. They stand in for different numbers in a problem. for example) a=12

7 0

3 years ago

Tony was Challenged to a half-court shooting competition. For every half-court shot that he makes, he will earn 20 points. For e

Mkey [24]

Answer:

Tony make 4 half-court shots and misses 16 half-court shots.

Step-by-step explanation:

Given:

Points earned for every successful, half-court shots = $20$

Points deducted for missing the shots = $5$ or $-5$

Total number of shots in the game = $20$

Final points earned by Tony = $0$

According to the question:

Let the number of successful half-court shot be $x$

And the number of shots missed be $20-x$

So,

In terms of points we can re-write it as:

⇒ $20(x)-5(20-x) =0$

⇒ $20x-100+5x=0$

⇒ $25x-100=0$

⇒ $25x-100+100=100$

⇒ $25x=100$

⇒ $\frac{25x}{25} =\frac{100}{25}$

⇒ $x=\frac{100}{25}$

⇒ $x=4$

Tony make 'x' shots that is 4 and the number of shot he missed is (20-x) =(20-4)=16

6 0

4 years ago

Can someone help me

erik [133]

Answer:

6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

(2x -12)/2 = arcsin(16/22×sin(24°))

x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

2x -12 = 0

x -6 = 0 . . . . . divide by 2

x = 6 . . . . . . . add 6

Then the range of values of x will be ...

6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

22² = AB² + AC² -2·AB·AC·cos(48°)

16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

22² = 2·AB²·(1-cos(48°))

16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0

3 years ago

Read 2 more answers

Chloe is paid $1,213.15 semimonthly. What is her average monthly net, or take-home, pay?

77julia77 [94]

HI THERE
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HOPE THAT HELPS

8 0

3 years ago

Read 2 more answers

a parking garage has 6 levels. Each level has 15 row. Each row has the same number of parking spaces. there are 2,250 parking sp

Mandarinka [93]

To start with, we know there’s a definite amount of parking spaces in all(2,250) and we also know each level(6 in all) had 15 rows of parking spaces.

Equation

A = Parking spots per row

A = 2,250 Divided by(6 levels times 15 rows)

A= 2,250 Divided by 90

A = 25

The correct answer is 25 parking spots per row

To check this answer we can do

25 spots per row, Times 15 rows per level, Times the total amount of levels (6)

= the total amount of parking spots

25*15*6= 2,250

True

This confirms this answer as correct. Hope this helps.

6 0

3 years ago