Answer:
Cartesian
z₁= 3 +4*j
z₂= 2 +3*j
Polar
z₁=5 * e^ (0.927*j)
z₁=√13 * e^ (0.982*j)
Step-by-step explanation:
for the complex numbers z the cartesian form of is
z= x + y*j
then
1) z₁= 3 +4*j (cartesian form)
2) z₂= 2 +3*j (cartesian form)
the polar form is
z= r* e^jθ
where
r= √(x²+y²) → r₁ = √(3²+4²) = 5 , r₂ = √(2²+3²) = √13
and
θ = tan⁻¹ (y/x) → θ₁ = tan⁻¹ (4/3)= 0.927 rad , θ₂ = tan⁻¹ (3/2)= 0.982 rad
then
z₁=5 * e^ (0.927*j)
z₁=√13 * e^ (0.982*j)
Suppose that the exponential growth function is y = 4^x.
If x = 1, then y = 4^1 = 4.
If x = 3, then y = 4^3 = 64.
Let the initial value be 1/2.
The growth function is now y = 1/2 * 4^x.
If x =1, then y = 2 which is half of the y value before adding the 1/2.
If x = 3, then y = 1/2 * 64 = 32.
Answer: 1/2
Answer -15 because it would be 15 but the negative would be turned into a negative again
Answer:
(-16.494 ; -3.506)
Step-by-step explanation:
student Prob A Prob B difference, d (A-B)
1 20 35____ - 15
2 30 40 ___ - 10
3 15 20 ___ - 5
4 40 50 __ - 10
Difference, d = -15, -10, -5, -10
Xd = Σd/ n = - 40 / 4 = - 10
Standard deviation of d ; Sd = 4.082
The confidence interval for the difference is given as :
Xd ± Tcritical*(Sd/√n)
Tcritical at 95%; df = n - 1 ; 4 - 1 = 3
Tcritical(0.05, 3)). = 3.182
C.I = -10 ± 3.182(4.082/√4)
C.I = -10 ± 6.494462
C. I = (-16.494 ; -3.506)
