Answer: 12 pounds.
Step-by-step explanation:
To solve this question, we'll use the direct proportion which is.
y = kx
Where,
y = weight on moon = 48 pounds
x = weight on Earth = 300 pounds
k = Unknown
y = kx
48 = 300k
k = 48/300
k = 0.16
The weight that a 75 pound object on Earth would weigh on the moon will be:
y = kx
where,
y = weight on moon = Unknown
k = 0.16
x = weight on Earth = 75 pounds
y = kx
y= 0.16 × 75
y = 12 pounds
The weight on the moon will be 12 pounds.
Here you would use right triangle trig (SOH CAH TOA)
So first draw a right triangle. Imagine youre standing at the angle opposite the right angle which is the one on the ground.This angle is the 41°. Now Imagine the balloon is as the angle above the right triangle. Well since the balloon is 1503 m from his location this would be the hypotenuse. SInce we are trying to find the height (x) we would use sine since
sine = opposite/hypotenuse . Now lets solve make sure calculator is in degree mode:
sin41 = x/1503 multiply both sides by 1503 to cancel it out
1503sin41 = x plug into calculator
x = 986.057 ft
The balloon is 986.057 feet above the ground.
The digit in the hundred thousands place is the 2
The product of 289 and 7 is somewhere between 289 and 2,100 .
