$\left\begin{array}{c|l}T&\qquad w(t)\\1&\dfrac{1}{1^2}=1\implies 1.00\\\\2&\dfrac{1}{2^2}=\dfrac{1}{4}\implies 0.25\\\\10&\dfrac{1}{10^2}=\dfrac{1}{100}\implies 0.01\\\\50&\dfrac{1}{50^2}=\dfrac{1}{2500}\implies 0.0004\\\\100&\dfrac{1}{100^2}=\dfrac{1}{10000}\implies 0.0001\\\\200&\dfrac{1}{200^2}=\dfrac{1}{40000}\implies 0.000025\\\\500&\dfrac{1}{500^2}=\dfrac{1}{250000}\implies 0.000004\\\\1000&\dfrac{1}{1000^2}=\dfrac{1}{100000}\implies 0.000001\\\end{array}\right$

4 0

2 years ago

Evaluate. 17 + 330 • 20 ÷ 102 ÷ 2 – 14

astra-53 [7]

The answer is 35.35294

6 0

2 years ago

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What is the value of x in the equation x - 2/3 + 1/6 = 5/6? 1) 4 2) 6 3) 8 4) 11

Licemer1 [7]

Answer:

$\large\boxed{x=\dfrac{4}{3}=1\dfrac{1}{3}}$

Step-by-step explanation:

$x-\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{5}{6}\qquad\text{multiply both sides by 6}\\\\6x-6\!\!\!\!\diagup^2\cdot\left(\dfrac{2}{3\!\!\!\!\diagup_1}\right)+6\!\!\!\!\diagup^1\cdot\left(\dfrac{1}{6\!\!\!\!\diagup_1}\right)=6\!\!\!\!\diagup^1\cdot\left(\dfrac{5}{6\!\!\!\!\diagup_1}\right)\\\\6x-(2)(2)+1=5\\\\6x-4+1=5\\\\6x-3=5\qquad\text{add 3 to both sides}\\\\6x=8\qquad\text{divide both sides by 6}\\\\x=\dfrac{8}{6}\\\\x=\dfrac{8:2}{6:2}\\\\x=\dfrac{4}{3}$

3 0

2 years ago

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