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Svet_ta [14]
3 years ago
7

How much will the store be selling the cans of spam if they want to make a 420% profit?

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

how many cans?

Step-by-step explanation:

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Help! Fast! Don't want to fail Please!
Marta_Voda [28]
1. 45
2. idk
3. See attached
4. 190

6 0
3 years ago
The circumference of circle x in which a = 49pi in squared
zzz [600]

Answer:

C = 14 pi inches

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

49 pi  = pi r^2

Divide each side by pi

49 pi/pi = pi /pi r^2

49 = r^2

Take the square root of each side

7 = r

The circumference is given by

C = 2 * pi *r

C = 2 * pi *7

C = 14 pi inches

8 0
3 years ago
The school choir is printing t-shirts for its members. The printing company charges a certain amount for each shirt plus a setup
belka [17]

Answer:

Each t-shirt costs about $9.46

Step-by-step explanation:

We can represent as the function

f(x)=28x+30

295=28x+30

265=28x

x=9.46

4 0
3 years ago
Read 2 more answers
Can someone help? Would be appreciated.
pickupchik [31]

Answer:

WOah

Step-by-step explanation:

5 0
3 years ago
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WILL MARK AS BRAINLIEST!!! 5. A 2011 study by The National Safety Council estimated that there are nearly 5.7 million traffic ac
Artyom0805 [142]

Answer:

Step-by-step explanation:

Hello!

Regarding the reasons that traffic accidents occur:

28% are caused by distracted drivers using cell phones or texting

11% of the drivers' user their phones at any time

The probability of a driver having an accident is 5.26%

a)

DC = event that a randomly selected driver is using a cell phone.

P(DC)= 0.11

b)

TA = event that a randomly selected driver has a traffic accident.

P(TA)= 0.0526

c) and f)

If both events are related, i.e. dependent, then you would expect that the occurrence of one of these events will affect the probability of the other one. If they are not related, i.e. independent events, then their probabilities will not be affected by the occurrence of one or another:

If both events are independent P(TA|DC)= P(TA)

If they are dependent, then:

P(TA|DC)≠ P(TA)

P(TA|DC)= 0.28

P(TA)= 0.0526

As you can see the probability of the driver having an accident given that he was using the cell phone is different from the probability of the driver having an accident. This means that both events are related.

d) and e)

You have to calculate the probability that "the driver was distracted with the phone given that he had an accident", symbolically P(DC|TA)

P(DC|TA) = \frac{P(DCnTA)}{P(TA)}

P(TA|DC)= \frac{P(TAnDC}{P(DC)} ⇒ P(DC∩TA)= P(TA|DC)*P(DC)= 0.28 *  0.11= 0.0308

P(DC|TA) = \frac{0.0308}{0.0526}= 0.585= 0.59

I hope this helps!

3 0
3 years ago
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