The percentage change in the staff strength of the grocery store is 10.53%.
<h3>How to find the percentage change?</h3>
We are given;
Number of employees in store = 38 employees
Number of additional people hired = 4 employees
Thus, percentage change in their staff is;
4/38 * 100% = 10.53%
Thus, the percentage change in the staff strength of the grocery store is 10.53%.
Read more about Percentage change at; brainly.com/question/2085058
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Answer:convergent
Step-by-step explanation:
Given
Improper Integral I is given as
integration of 
is
![I=1000\times \left [ e^x\right ]^{0}_{-\infty}](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5Ex%5Cright%20%5D%5E%7B0%7D_%7B-%5Cinfty%7D)
![I=1000\times I=\left [ e^0-e^{-\infty}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20I%3D%5Cleft%20%5B%20e%5E0-e%5E%7B-%5Cinfty%7D%5Cright%20%5D)
![I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5E0-%5Cfrac%7B1%7D%7Be%5E%7B%5Cinfty%7D%7D%5Cright%20%5D)
so the integration converges to 1000 units
There is no solution is the answer. I had this in one of my math tests so I'm positive it's correct :D
The answer is 5-3/2x. Hope this helps :)
Answer:
A. The next 3 terms are —9, —11, —13
B. The sequence is Arithmetic
C. The sequence has a common difference of —2
Common difference = T2 — T1 or = T3 — T2
=T2 — T1 = —3 —(—1) = —2 or
= T3 — T2 = —5 —(—3) = —2
D. Tn = a + d(n—1)
a = first term = —1
d = Common difference = —2
n = 27
T27 = —1 + —2(27—1)
T27 = —1 + —2(26)
T27 = —1 —52
T27 = —53
