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Naya [18.7K]
3 years ago
5

You flip a nickel 100 times and record your results: 35 heads and 65 tails. From your experimental data, what is the probability

of the nickel landing on tails? Round to the nearest whole percent.
Mathematics
2 answers:
Cloud [144]3 years ago
7 0
You divide 100 by 65 and you get 2%
musickatia [10]3 years ago
4 0
Out of 100 flips, the nickel landed on tails 65 times.

P(tails)=65/100 or 0.65 or 65%

Answer 65%
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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
rosijanka [135]

y - 0 = 5(x-4)

  y = 5x-20

  5x - y = 20  Standard Form  


3 0
3 years ago
The prime factorization of 441 is
OLga [1]

441 is odd, so we can't divide it by 2.

Since the sum of its digits is 4+4+1=9, which is divisible by 3, we can divide 441 by 3, and we have

441\div 3=147

Which is still divisible by 3, because 1+4+7=12. We have

147\div 3=49

49 is not divisible by 3 anymore, nor by 5 (it doesn't end with 0 or 5).

It is divisible by 7 though, we have

49\div 7=7

and finally,

7\div 7=1

So, the factorization of 441 is

441=3^2\times 7^2

8 0
3 years ago
Read 2 more answers
The sum of three numbers is 104. The first number is 10 less than the second. The third number is 4 times the second. What are t
Shalnov [3]

Answer:

The numbers are 9, 19 and 76.

Step-by-step explanation:

Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.

The first number in terms of x:

x - 10

The second number in terms of x:

4x

If we add them all up, these 3 numbers in terms of x must be equal to 104, so:

x + (x - 10) + (4x) = 104 \\ x + x - 10 + 4x = 104 \\ 6x - 10 = 104 \\ 6x = 114 \\ x = 19

Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:

19 - 10 = 9

4 \times 19 = 76

The first number is 9, second number 19 and the third number 76.

6 0
3 years ago
How many repeating digits are in <br><br> 1<br> 2<br> 3<br> 4
Alina [70]

Answer:

infinite

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve for the given length. The length of a rectangle is 3m longer than its width. The area of the rectangle is 154^2. What is t
Andre45 [30]
If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
7 0
3 years ago
Read 2 more answers
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