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3 years ago

The value of a car depreciates by 35% per year. Work out the current value of a car bought 2 years ago for £20000

Mathematics

1 answer:

Rzqust [24]3 years ago

6 0

First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;

Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.

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Rewrite the numbers from least to greatest 0.33,-0.12,-0.127,0.2,45/10

Sonbull [250]

-0.127
-0.12
0.20
0.33
45/10
I think that is right

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3 years ago

Read 2 more answers

Find the measures of the following angles.

makvit [3.9K]

Answer:

1: 36° 2: 122° 3: 122° 4: 38°

Step-by-step explanation:

First start out by getting 2 and 3. so 58+angle 3 has to sum to 180° since they are supplementary and are a straight line. So 180-58=122. Angle 2 is the same since theyre vertical. then since a triangle has 180° total, you subtract from 180 to find the final angle measurement.

5 0

3 years ago

Find a common difference of the arithmetic sequence -2, -1 4/5, -1 3/5, -1 2/5,

elixir [45]

Answer:

The common difference is $\frac{1}{5}$ or 0.2

Step-by-step explanation:

Given:

Arithmetic Sequence -2, -1 4/5, -1 3/5, -1 2/5,

First term = a₁ = -2

Second term = a₂ = $\frac{-9}{5}$

Third term = a₃ = $\frac{-8}{5}$

Fourth term = a₄ = $\frac{-7}{5}$

To Find:

Common Difference = d = ?

Solution:

Formula for Common Difference d , $\textrm{common difference}= \textrm{Second Term} -\textrm{First Term}=\textrm{Third Term}-\textrm{Second Term}$

$\textrm{common difference} = a_{2}- a_{1}= a_{3}- a_{2}=a_{4}- a_{3}$

∴ $d = \frac{-9}{5}-(-2)\\d=\frac{-9}{5}+2\\d=\frac{1}{5}\\ \therefore d =0.2\\$

The common difference is $\frac{1}{5}$ or 0.2

6 0

3 years ago

Almost all companies utilize some type of year-end performance review for their employees. Human Resource (HR) at a university's

balu736 [363]

Answer:

The Answer is 76.

Step-by-step explanation:

Given the normal distribution " 10% of employees (rated) exemplary, 20% distinguished, 40% competent, 20% marginal, and 10% unacceptable'', we can see that exemplary employees are top 10% rated employees.

We have the formula for normal distribution:

z=(X-M)÷σ

where z is the minimum z-score for top 10% employee, X is the minimum score for top 10% employee, M is the mean of the score distribution, σ is the standard deviation of the score distribution.

The z-score we are looking for is the value "a" that separates the highest 10% from the lowest 90% i.e. P(z≤a)=0.90

If we look at z-table, corresponding value for a is 1.28155

We can now put the values in the formula:

1.28155= $\frac{X-50}{20}$

So X=(1.28155×20)+50=75.631

Therefore minimum score for exemplary employee is 76.

3 0

3 years ago

A salesperson at a jewelers store earns 5% commission each week. Last week, heidi sold $530 worth of jewelry. How much did she m

V125BC [204]

Answer:

the salesperson earned 5% which is; $26.5 then subtract 26.5 from the total made to find out how much the store made which is: $503.5

Step-by-step explanation:

5 0

2 years ago