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2 years ago

PLS ANSWER NOW ,, ILL GIVE BRAINLY :)

Mathematics

2 answers:

wariber [46]2 years ago

4 0

Answer:

The answer is B!

drek231 [11]2 years ago

3 0

Answer:

Table b

:> Hope this helps

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3.) You deposited $5,000 in an account that pays 4% annual interest. Find the

Maurinko [17]

The balance after one year is $5200

Step-by-step explanation:

The formula to apply here is

$A=P(1+\frac{r}{n} )^{nt}$

where

A=Amount of money at the end of the period=?

P=the amount of money invested= $5000

r=rate of interest=4%=0.04

n=number of compounding per year=1

t=time in years=1

Applying the formula

$A=P(1+\frac{r}{n} )^{nt} \\\\\\A=5000(1+\frac{0.04}{1} )^{1} \\\\\\A=5000(1.04)\\\\A=5200$

A=$5200

Learn More

Compound Interest: brainly.com/question/12148233

Keywords : interest, compounded annually

#learnwithbrainly

6 0

3 years ago

Write an equation of the line below.

otez555 [7]

Answer:

im not exactly sure but i think it would be y=1x-2

7 0

2 years ago

1.<br> |x+5|=3<br><br> How do I get this again?

Tatiana [17]

-2 because 3-5 = -2

7 0

3 years ago

Can someone help me find the equation for this line please

pogonyaev

Answer:

y = x + 1

Step-by-step explanation:

The line y = x goes through the origin, and forms a perfect 45 degree angle with the x axis.

This is that same line, moved upward 1 unit, so the y value comes out 1 unit more.

Also, in y = mx + b form (slope-intercept form), we see slope m = 1 and y-intercept b = 1, so

y = 1x + 1 = x + 1

y = x + 1

5 0

2 years ago

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

$\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

$\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}$

And canceling out the sin^2 x leaves us with just

$cos^2x-sin^2x$ which is one of our identities.

5 0

3 years ago