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Ulleksa [173]
3 years ago
13

Shaun estimated that the attendance at a college game was 1,200 people. The actual attendance was 1,158. What is the percent err

or of Shaun's estimate? (Round your answer to the nearest tenth) HELP!!! PLEASE THIS IS MY LAST POINT I CAN DO PLEASE PLEASEPLEAPLEAPLEAPLSEPAEEASE HELP
Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

3.5%

Step-by-step explanation:

1200-1158=42

42/1200 =0.035

0.035×100=3.5%

You might be interested in
Guess the mystery number...
Snowcat [4.5K]
<span>The number is less than 190,000 and greater than 180,000
5,000 more than the number has 187 thousands
2000 less than the number has 4 hundreds

180, 000 <n> 190, 000</span>
180,000 + 2000 = n = 5000-187, 000
182,000 = n = 182, 000  
Or, 
 <span>180, 000 <n> 190,000      </span>               
 <span>n + 5000= 187, 000                           n – 2000 = 180, 000</span> <span>
 n= 187, 000- 5000                             n = 180, 000 + 2000</span> <span>
 n= 182, 000                                       n= 182, 000</span>



6 0
3 years ago
A rancher uses a water bowl for her dog that holds 8,500 milliliters and a water trough for her
Vlad1618 [11]

Answer: The rancher will use 8527 milliliters to fill both the bowl and the trough.

Step-by-step explanation:

Since we have given that

Quantity of water bowl for her dog = 8500 milliliters

Quantity of water trough for her horse = 27 milliliters

Total quantity of water that the rancher will used to completely fill both the bowl and the trough is given by

8500+27\\\\=8527\ milliliters

Hence, the rancher will use 8527 milliliters to fill both the bowl and the trough.

8 0
3 years ago
A poster of area 24,000 cm2 has blank margins of width 10 cm on the top and bottom and 6 cm on the sides. find the dimensions th
bogdanovich [222]

The total poster area is:

A = (l + 20) (w + 12)

where l and w is the length and width of the printed area

24000 = (l + 20) (w + 12)

l = [24000/(w + 12)] – 20

 

The printed area is simply:

a = l w

substituting l:

a = ([24000/(w + 12)] – 20) w

a = (24000w)(w + 12)^-1 – 20 w

Taking the first derivative da/dw:

da/dw = (24000)(w + 12)^-1 - (24000w)(w + 12)^-2 – 20

Set da/dw = 0:

(24000)/(w + 12) - (24000w)/(w + 12)^2 – 20 = 0

Multiply everything by (w + 12)^2:

24000 (w + 12) – 24000w - 20(w + 12)^2 = 0

24000w + 288000 – 24000w – 20 (w^2 + 24w + 144) = 0

-20 w^2 – 480 w + 285120 = 0

w^2 + 24 w = 14256

Completing the square:

(w + 12)^2 = 14256 + 12^2

w + 12 = ±120

w = 108 cm

 

l = [24000/(w + 12)] – 20

l = [24000/(108 + 12)] – 20

l = 180 cm

 

Therefore the dimensions of the whole poster are:

w + 12 = 120 cm

l + 20 = 200 cm

 

The poster should be 200 cm x 120 cm

<span> </span>

6 0
3 years ago
Write the index for 2^2 x2^3
fredd [130]

Answer:

2^5

Step-by-step explanation:

7 0
3 years ago
Subtract 5a-6b+7c from 13a-4b+8c
schepotkina [342]

Answer:

im not sure but i think the anwser is its self dont take my anwser its garbadge

Step-by-step explanation:

8 0
3 years ago
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