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hodyreva [135]
3 years ago
13

Graph y < x and y ≥ 4x + 2

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

Image is attached.

Step-by-step explanation:

Remember since the blue line is greater than, instead of being dashed like the red line, it's solid.

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Hey plsss help meeeeee
nalin [4]

Answer:

The first, third, and fourth answer choices represent a function.

Step-by-step explanation:

A relation is a relationship between sets of values. The two quantities that are being related to each other are the input (x-variable) and the output (y-variable). But relations in general aren't always a good way to relate between x and y.

Say that I have situation where I want to give <em>x </em>dollars to the cashier so he can change them to <em>y</em> quarters. Here is a "example" of the relation:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       2       |          12

Do you see something wrong here? Yes! We all know that you can't exchange 2 dollars for 12 quarters. You can only exchange 2 dollars for 8 quarters and only 8 quarters. This is a general reason why we don't rely on general relations for real-life situations. One x-variable does not exactly map to one and only one y-variable.

However, a relation that can map one x-variable to one and only one y-variable is known as a function. Let's make the above example an actual function to prove a point:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       3       |          12

Now, the 3 dollars make 12 quarters as it should. This is how a function should look like.

There are two ways to check if a relation is a function. On a relation, table, or a set of ordered pairs, you have to make sure there is no "x-variable" that repeats. All x-values of a relation have to be unique in order to be a function. On a graph, you can also perform the Vertical Line Test. If you draw vertical lines over a relation and if the lines cross only once, then it is a function. If not, it fails the Vertical Line Test.

So to answer you're question, the first, third, and fourth choices are functions because they all have unique x-variables. The second choice is not a function because it fails the Vertical Line Test.

7 0
3 years ago
Defined as bounded by two distinct end points that contain every point on the line between its end points.
Alja [10]
This would be the term referred to as a line segment. I hope this helps!
8 0
3 years ago
Read 2 more answers
How many complex roots does the polynomial equation below have? x^5 - 3 = 0
const2013 [10]

For any polynomial equation, The Fundamental Theorem of Algebra tells you that the highest degree present will tell you how many complex roots the equation has. There are only two terms, "x^{5}" and "3". The x^{5} term has a degree of 5, its exponent. The 3 term has a degree of zero, because you could write it as 3 * x^{0} = 3 * 1 using the zero exponent rule.


The degrees present are 5 and 0. Choose the highest one, 5. So, the answer here is D.

8 0
3 years ago
Respond pls <br> To get some points
Ipatiy [6.2K]
<h2>Answer:</h2>

1/2

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • The school football team has a match tomorrow
  • The probability of the team winning is 1/6
  • The probability of the team drawing is 2/6

<h3>Asked :</h3>
  • The probability of the team losing

<h3>Solution :</h3>

Probability of the team losing the match = 1 - 1/6 - 2/6

Probability of the team losing the match = 6/6 - 1/6 - 2/6

Probability of the team losing the match = 3/6

Probability of the team losing the match = 1/2

<h3>Conclusion :</h3>

The probability of the team losing the match is 1/2

7 0
2 years ago
Solve for x: 5x-4(х+3)=8
Aleksandr [31]

Answer:

x=20

Step-by-step explanation:

7 0
3 years ago
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