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Brilliant_brown [7]
3 years ago
14

Ldentify the slope and yintercept of the function y = 3x- 6.

Mathematics
1 answer:
Katarina [22]3 years ago
8 0

QUESTION:

Identify the slope and y-intercept of the function y = 3x - 6

ANSWER:

In all choices the correct answer is \green{\boxed{B}}

Slope: \green{{3}}

y-intercept: \green{{0, -6}}

EXPLANATION:

The slope-intercept form is \blue{{y = mx + b,}} where \blue{{m}} is the slope and \blue{{b}} is the y-intercept

\green{{y = mx + b}}

Find the values of \blue{{m}} and \blue{{b}} using the form:

\green{{y = mx + b}}

\green{{m = 3}}

\green{{b = -6}}

The slope of the line is the value of \blue{{m}}, and the y-intercept is the value of \blue{{b}}

Slope: \green{\boxed{3}}

y-intercept: \green{\boxed{(0, -6)}}

hope it's helps

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Jackson purchases a new car for $48,000. The car's value can be modeled by the following exponential function: y = 48,000(0.76)^
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Which set of integers represents the lengths of the sides of an isosceles triangle? A. {6,6,5} B. {3,4,5} C. {15,5,10} D. {1,1,3
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4 years ago
Simplify csc θ(1−cos^2 θ)/sinθ cos θ to a single trigonometric function
topjm [15]

Answer:

<u><em></em></u>\frac{cosec\alpha(1-cosx^{2} \alpha ) }{sin\alpha cos\alpha  } = sec\alpha<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the trigonometric function

            \frac{cosec\alpha(1-cosx^{2} \alpha ) }{sin\alpha cos\alpha  }

  we know that    sin²∝ + cos²∝ = 1

                      ⇒    sin²∝ = 1- cos²∝

Now we have to simplify the given trigonometric function

                =       \frac{cosec\alpha(sin^{2} \alpha  ) }{sin\alpha cos\alpha  }

               =       \frac{cosec\alpha(sin \alpha  ) }{ cos\alpha  }

<u><em>Step(ii)</em></u>

         we know that  cosec∝ = 1/ sin∝

              = \frac{\frac{1}{sin\alpha } (sin \alpha  ) }{ cos\alpha  }

    After cancellation sine function, we get

          =  \frac{1 }{ cos\alpha  } = sec\alpha

<u><em>Final answer:-</em></u>

<u><em></em></u>\frac{cosec\alpha(1-cosx^{2} \alpha ) }{sin\alpha cos\alpha  } = sec\alpha<u><em></em></u>

           

     

 

               

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