1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatuchka [14]
2 years ago
11

Can someone help me pleaseeee????

Mathematics
1 answer:
Lesechka [4]2 years ago
8 0

Answer:

CA=20  CD=20

AB=23  DE=23

BC=29  EC=29

Step-by-step explanation:

You might be interested in
Combine the like terms to simplify the expression 2x+3y-5x+4y-8z
SIZIF [17.4K]

Answer:

7y-3x-8z

Step-by-step explanation:

(3y+4y)+(2x-5x)-8z

7y+(2x-5x)-8z

7y-3x-8z

6 0
2 years ago
8 cupcakes cost $32. What is the unit cost per cupcake?
MakcuM [25]
$0.25

Used calculator!
5 0
2 years ago
Read 2 more answers
Tan(x-y) if cscx=13/5 and coty=4/3
ehidna [41]

Answer:

tan(x-y) = -16/63

Step-by-step explanation

Tan(x-y) if cscx=13/5 and coty=4/3

Given

coty = 4

1/tany = 4/3

Cross multiply

tan y = 3/4

Also since cscx = 13/5

1/sinx = 13/5

sinx = 5/13

Since sinx = opp/hyp

opp = 5

hyp = 13

Get the adjacent

hyp² = opp²+adj²

13² = 5²+adj²

adj² = 13² - 5²

adj² = 169 - 25

adj² = 144

adj = 12

cosx = adj/hyp

cosx = 12/13

tanx = sinx/cosx

tanx = (5/13)/(12/13)

tanx = 5/13 * 13/12

tan x = 5/12

tan(x-y) = tanx - tany/1+tanxtany

tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)

tan(x-y) = (5-9/12)/1+5/16

tan(x-y) = -4/12/(21/16)

tan(x-y) = -1/3 * 16/21

tan(x-y) = -16/63

3 0
2 years ago
A student scored 75 and 97 on her first two quizzes. Write and solve a compound inequality to find the possible values for a thi
Rainbow [258]

Answer:

85 \le \frac{75 + 97 + n}{3} \le 90; 83 \le n \le 98

Step-by-step explanation:

Score of the first two quizzes: 75 and 97

Let n represent the third score

Average score would be: \frac{75 + 97 + n}{3}.

Given that the average score fall between 85 and 90, this can be represented by the compound inequality as shown below:

85 \le \frac{75 + 97 + n}{3} \le 90

Solve for n in each statement that makes up the compound inequality:

85 \le \frac{75 + 97 + n}{3}

85 \le \frac{172 + n}{3}

Multiply both sides by 3

85*3 \le 172 + n

255 \le 172 + n

Subtract 172 from each side of the inequality

255 - 172 \le n

83 \le n

Also,

\frac{75 + 97 + n}{3} \le 90

\frac{172 + n}{3} \le 90

Multiply both sides by 3

172 + n \le 90*3

172 + n \le 270

Subtract 172 from both sides of the inequality

n \le 270 - 172

n \le 98

Combining both together, the possible values of her third quiz score would be:

83 \le n \le 98

3 0
2 years ago
0.10 x 37.7 explain please
kodGreya [7K]

Answer: The answer is 3.77.

Explanation: Since 0.10 is 10 times smaller than 1, we know that if we divide 37.7 by 10, we will get the same answer as 0.10 x 37.7.

5 0
2 years ago
Other questions:
  • Don has three more than twice as many quarters as Greg if they have 18 quarters altogether how many quarters does Don have
    14·2 answers
  • Simplify 3/2x+5+5/x-5
    11·2 answers
  • Prove that if n is a positive integer, then n is even if and only if 7n 4 is even.
    14·1 answer
  • Find the slope of line that contains the points (-4,-13) and (8,5).
    12·2 answers
  • Eric and Stephanie took their younger sister Melissa to pick apples. Eric picked 4 times as many apple as Melissa. Stephanie pic
    15·1 answer
  • PLEASE HELP I need help on these questions
    15·1 answer
  • A store carries four brands of DVD​ players, J,​ G, P and S. From past​ records, the manager found that the relative frequency o
    13·1 answer
  • Convert 192 ounces to pounds. Round to the nearest hundredth if necessary.<br> QUICK PLEASE
    8·2 answers
  • A<br> rope<br> cut off?<br> is 3m long. If 25% is cut off, how many cm was<br> 25% of 3
    10·1 answer
  • Trey has 75 in his saving account. Each month he deposits 25 into the account. Which expression shows the amount of money that T
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!