The matrix equation that represents this situation is
![\left[\begin{array}{ccc}3&2&0\\1&0&4\\3&1&1\end{array}\right]*\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}13.50\\16.50\\14.00\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%262%260%5C%5C1%260%264%5C%5C3%261%261%5Cend%7Barray%7D%5Cright%5D%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D13.50%5C%5C16.50%5C%5C14.00%5Cend%7Barray%7D%5Cright%5D%20)
Use technology to find the inverse of matrix A:
![A^{-1}= \left[\begin{array}{ccc}-\frac{2}{5}&-\frac{1}{5}&\frac{4}{5}\\ \frac{11}{10}&\frac{3}{10}&-\frac{6}{5}\\\frac{1}{10}&\frac{3}{10}&-\frac{1}{5}\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-%5Cfrac%7B2%7D%7B5%7D%26-%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B4%7D%7B5%7D%5C%5C%0A%5Cfrac%7B11%7D%7B10%7D%26%5Cfrac%7B3%7D%7B10%7D%26-%5Cfrac%7B6%7D%7B5%7D%5C%5C%5Cfrac%7B1%7D%7B10%7D%26%5Cfrac%7B3%7D%7B10%7D%26-%5Cfrac%7B1%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D%20)
Multiplying A inverse by B, we get the solution matrix
[tex]\left[\begin{array}{ccc}2.50\\3\\3.50\end{array}\right][\tex]
Answer:
x=4
Step-by-step explanation:
Let's solve your equation step-by-step.
−x=2−3x+6
Step 1: Simplify both sides of the equation.
−x=2−3x+6
−x=2+−3x+6
−x=(−3x)+(2+6)(Combine Like Terms)
−x=−3x+8
−x=−3x+8
Step 2: Add 3x to both sides.
−x+3x=−3x+8+3x
2x=8
Step 3: Divide both sides by 2.
2x/2 = 8/2
x=4
Answer: Neither
Step-by-step explanation: Neither, because both samples will supply the same information about their likely population.
Answer:
A and C
Step-by-step explanation:
![\left (2^{\frac{1}{6}} \right)^{9} = 2^{\frac{3}{2}} = \left (2^{3} \right)^\frac{1}{2}= 8^{\frac{1}{2}} = \sqrt{8}\\\left (2^{\frac{1}{6}} \right)^{9} = \left(2^{9}\right)^{\frac{1}{6}} = \left(512\right)^{\frac{1}{6}}= \sqrt[6] {512}](https://tex.z-dn.net/?f=%5Cleft%20%282%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%20%5Cright%29%5E%7B9%7D%20%3D%202%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%20%3D%20%5Cleft%20%282%5E%7B3%7D%20%5Cright%29%5E%5Cfrac%7B1%7D%7B2%7D%3D%208%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Csqrt%7B8%7D%5C%5C%5Cleft%20%282%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%20%5Cright%29%5E%7B9%7D%20%3D%20%5Cleft%282%5E%7B9%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%20%3D%20%5Cleft%28512%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%3D%20%5Csqrt%5B6%5D%20%7B512%7D)
Answer:
A. 200 packages
Step-by-step explanation:
The number of packages per roll can be found by dividing the length of a roll by the length of tape needed for each package.
__
For each package:
(2.375 in/piece)×(4 piece/package) = 9.5 in/package
Per roll:
(1900 in/roll) / (9.5 in/package) = (1900/9.5) packages/roll
= 200 packages/roll
The machine can seal 200 packages with a roll of tape 1900 inches long.
