Answer:
15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 25 charged purchases and a standard distribution of 2
This means that 
Proportion above 27
1 subtracted by the pvalue of Z when X = 27. So



has a pvalue of 0.8413
1 - 0.8413 = 0.1587
Out of the total number of cardholders about how many would you expect are charging 27 or more in the study?
0.1587*100% = 15.87%
15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.
Slot method
1st slot, 5 options
2nd slot, 4 options (1 gone to the first slot)
3rd slot, 3 options (1 gone again)
4th slot,2 options (1 less)
multiply
5*4*3*2=120
answer is 120 arrangements
Answer:
2 x 7 inches is 14 inches
Step-by-step explanation:
Answer:
Step-by-step explanation:
x = y - 2.........(1)
4x + y = 2......(2)
Substituting x in (1) in (2)
4(y - 2) + y = 2
4y - 8 + y = 2
5y = 2 + 8
5y = 10
y = 10/5
y = 2
Putting x in (1)
x = y - 2
x = 2 - 2
x = 0
Answer:
Limit is 2
Step-by-step explanation:
The last term approaches zero as n approaches infinity so the fuction approaches 2.