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Travka [436]
3 years ago
13

I know the answer is right but it said it’s wrong. Can I get a second answer to make sure? Thank you so much!

Mathematics
1 answer:
ad-work [718]3 years ago
6 0

Answer:

   70.3 ft

Step-by-step explanation:

The ratio of the adjacent side (33 or KM) to the hypotenuse (X or KL) is the cosine of the angle:

  cos(62°) = 33/KL

Multiplying by KL/cos(62°) gives ...

  KL = 33/cos(62°) ≈ 33/0.4694 ≈ 70.292 ≈ 70.3

The length of KL is about 70.3 feet.

___

Make sure your calculator is in degrees mode.

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Which lines are perpendicular to the line y - 1 = 1/3 (x+2)? Check all that apply.
ioda

Answer: Options 1, 3, 5

Step-by-step explanation:

Perpendicular lines have slopes that are negative reciprocals, so since the slope of the given line is 1/3, we need to find lines with a slope of -3.

  • Option 1 has a slope of -3.
  • Option 2 has a slope of 3.
  • Option 3 has a slope of -3.
  • Option 4 has a slope of 1/3.
  • If we subtract 3x from both sides, we get y=-3x+7, so option 5 has a slope of -3.
7 0
2 years ago
Select the correct answer. What is the ratio of the length of to the length of ? A. B. C. D.
erik [133]

Answer: b is the answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose 15% of x equals 20% of y. What percentage of x is y ?
WINSTONCH [101]

Answer:

x = 133\frac{1}{3} of y

Step-by-step explanation:

Given:

15% of x equals 20% of y

So,

0.15x = 0.20y

so

x = 0.20 y / 0.15

x = 1.3333y

x = 133\frac{1}{3} of y

7 0
2 years ago
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What is the length of the shadow cast by a 12-foot lamp post when the angle of elevation of the sun is 60º? (to the nearest tent
elena-s [515]

Answer:

6.9 foot.

Step-by-step explanation:

Given: Length of lamp post= 12-foot.

           The angle of elevation of the sun is 60°.

∴ The length of Lamp post, which is opposite is 12-foot.

  Now, finding the length of shadow cast by foot lamp.

Length of shadow is adjacent.

∴ We know the formula for Tan\theta= \frac{Opposite}{adjacent}

Next, putting the value in the formula.

⇒ Tan 60° = \frac{12}{adjacent}

Cross multiplying both side and using the value of Tan 60°

∴ Adjacent= \frac{12}{\sqrt{3} } = 6.92 ≅ 6.9 (nearest tenth value)

6.9 is the length of shadow cast by a 12-foot lamp post.

3 0
3 years ago
4n^(2)+4n=3<br> Please help with the work
Kaylis [27]

Answer:

n= 1/2 ( \frac{1}{2} )  or  (0.5)

AND

n= -3/2 ( -\frac{3}{2} ) or (-1.5)

Step-by-step explanation:

4n^2+4n=3

step1: move 3 to the other side and make the equation equal to zero.

4n^2+4n-3=0

step2: factorise the equation.

(2n-1)(2n+3)=0

step3: make each bracket equal to zero.

2n-1=0

2n+3=0

step4: solve for n values.

<u>1.</u> 2n-1=0

(add 1 for both sides)

2n=1

(divide by 2 for both sides)

n= 1/2 ( \frac{1}{2} )  or  (0.5)

<u>2.</u> 2n+3=0

( subtract 3 for both sides)

2n=-3

(divide by 2 for both sides)

n= -3/2 ( -\frac{3}{2} ) or (-1.5)

3 0
2 years ago
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