Hello,
The correct order is:
-16.5, -√270, -50/30, 16 3/10
Faith xoxo
Given:
In ΔHIJ, h = 40 cm, ∠J=20° and ∠H=93°.
To find:
The length of j, to the nearest centimeter.
Solution:
According to Law of sine,
In ΔHIJ, using law of sine, we get
On further simplification, we get
Approximate the value to the nearest centimeter.
Therefore, the length of j is 14 cm.
Zeros are
Write in factor form and solve
- (x-0)(x-(-3))(x-(-4))=0
- x(x+3)(x+4)=0
- x[x(x+4)+3(x+4)]=0
- x(x²+4x+3x+12)=0
- x(x²+7x+12)=0
- x³+7x²+12x=0
Points given (-2,16)
Solve for n
On solving we get
So the function is
- y=-4(x³+7x²+12x)
- y=-4x³-28x²-48x
5.09
rule is A = C^2
____
4π
area is equal to C power 2 then everything divided by 4π
The volume of a sphere is 4/3 pi, times its radius cubed.
To cube the radius you multiply the radius times itself 3 times.
3 x 3 x 3 =27
4/3 pi x 27 = 113.1.
113.1 rounded to the nearest tenth is the same.
