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3 years ago

Some please help and explain the steps. Tysmmmmm

Mathematics

1 answer:

-Dominant- [34]3 years ago

5 0

Answer:

since angle B and angle C contains the same arc AD. set the angles equal

11x-3=8x+15

x=6

so the angle has a measure of 63 degrees

the central angle is the angle of the arc

and it is always 2 times the angle that we just that contains the arc but does touches the end of the circle.

so its 63 *2 =126 degrees.

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2. How can Diego package all the 64 cookies so that each bag has the same number of them? How many bags can he make, and how man

Readme [11.4K]

Divide 64 by multiple numbers, and if they divide evenly that’s how many will be in each bag for the number of bags (number you divided by). For example, dividing 64 by 8 (bags) would be 8 cookies in each bag. You can do this with multiple numbers as long as it goes in evenly

7 0

3 years ago

A bag contains 14 green, 12 orange and 19 purple tennis balls.

Nataliya [291]

Answer:

See explanation

Step-by-step explanation:

There are 14 green, 12 orange and 19 purple tennis balls in the bag,

$14+12+19=45$ balls in total.

A. The propbabilities that

a randomly chosen ball from the bag is green $=\dfrac{14}{45};$

a randomly chosen ball from the bag is orange $=\dfrac{12}{45}=\dfrac{4}{15};$

a randomly chosen ball from the bag is purple $=\dfrac{19}{45}.$

A probability model for choosing a tennis ball from the bag is

$\begin{array}{lccc}\text{Ball}&\text{Green}&\text{Orange}&\text{Purple}\\ \\\text{Probability}&\dfrac{14}{45}&\dfrac{4}{15}&\dfrac{19}{45}\end{array}$

B. Suppose a tennis ball is randomly selected and then replaced 75 times. You can expect that orange ball appear

$\dfrac{4}{15}\times 75=4\times 5=20$ times

5 0

3 years ago

Persons younger than 18 years old are not eligible to vote. Let a be age in years.

Usimov [2.4K]

Younger than = less than

Less than symbol = <

People cannot have a negative age, so a must be positive

B. <span>a < 18 and a must be a positive number</span>

8 0

3 years ago

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b

Korolek [52]

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

4 0

3 years ago

Which expression is equivalent to 5(2x + 10)?

Reika [66]

It’s E because if your multiply 5 x 2x u get 10x and 10 x5 = 50 so our answer is E 10x +50

4 0

2 years ago

Read 2 more answers