Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
eing able to make change for a dollar? Of there are multiple selections of the coins that will work choose the selection with the largest total numbers of coins.
Let x= number rows Then x + 5 = number of seats per row
x(x+5) = 126 X^2 + 5x = 126 x^2 + 5x -126 = 0; now factor or use quadratic: (x+14)(x-9) = 0; so the answers are either -14, or 9, and since -14 is not possible in this case because you can't have a negative number of rows, the answer is 9 rows.
Check work: number of rows = 9, number of seats per row = 9+ 5= 14, and 9 x 14 = 126
1/4 = 2/8. Remember that. This means that 1/8 is equal to half of a month. It there is 5/8, you can add a half month for every eight. In this case, it will take 2 and a half months