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3 years ago

Rewrite the equation by completing the square. 2x^{2}-3x-5 = 0

Mathematics

1 answer:

mylen [45]3 years ago

7 0

Answer:

2x^{2}-3x-5 = 0

use the formula (b/2)^2 in order to create a new term. Solve for x by using this term to complete the square.

x= 5/2, -1

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Evaluate -1/2A when

elena-14-01-66 [18.8K]

Answer: B, No solution

Actual answer is:

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4 years ago

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Suppose there is a mutation in a laminin-binding integrin gene that causes a loss of function in the cytoplasmic domains of the

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Answer:

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3 years ago

What does this mean-Solve 3!

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Answer:

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3 years ago

An educator wants to determine whether a new curriculum significantly improves standardized test scores for third grade students

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Answer:

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4 years ago

I’m having trouble with this problem. Please help

iVinArrow [24]

The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is

$\vec r(t) = \sin(t) \, \vec\imath + 4t^3 \, \vec\jmath + 5t \, \vec k$

Differentiate twice with respect to time $t$ to get the velocity and acceleration vectors, respectively:

$\dfrac{d\vec r}{dt} = \vec v(t) = \cos(t) \,\vec\imath + 12t^2 \,\vec\jmath + 5 \,\vec k$

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which most closely resembles the first choice.

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2 years ago