Answer:
Vertex: (3,0)
Max/min: min
axis of symmetry: x=3
Domain: (-∞,∞)
Range: [3,∞)
zeroes: (3,0)
Step-by-step explanation:
Vertex is where the graph changes directions (so in this case it's the point where it changes from decreasing to increasing) which I think is (3,0)
It's a minimum because the coefficent for the degree is positive
The axis of symmetry is just the x value of the vertex (which is x= 3)
the domain is all possible x values (-∞,∞)
The range is all possible y values [3,∞)
The zeroes is where the line hits the x axis, which is (3,0)
I can't see the whole pic...
what is written on the side?? I can see part of it and I think it is telling you what to do. If not what is thew question?? All you are showing is the lines.
Answer:
B y = -1/2x + 7/2
Step-by-step explanation:
We know that it has a negative slope since the points go from the top left to the bottom right
We can eliminate A and D
The y intercept is where it crosses the y axis
It should cross somewhere between 2 and 4
C has a y intercept of 9 which is too big
Lets verify with a point
x = -4
y = -4(-4)+9 = 16+9 = 25 (-4,25) not even close to being near the points on the graph
checking B
y = -1/2 (-4) +7/2
= 2 + 7/2 = 11/2 = 5.5 it seems reasonable
Answer:
Option 1: CD is a perpendicular bisector of AB
Step-by-step explanation:
Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.
Formula to find slope

Formula to Find Distance between two points

mAB ( represents , Slope of AB )
1. 
2. 
3. 
4. 
5. 
mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is 



Hence CD ⊥ AB
Also
From Point 4 and point 5 above , we see that
AC = CB
Hence CD bisect AB at C, also CD ⊥ AB
There fore
CD is a perpendicular bisector of AB
Therefor option 1 is true