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Rudik [331]
3 years ago
13

Two imaginary roots A.144 B.O D.-4 C.36

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

D) -4 (with imaginary roots ±2i)

Step-by-step explanation:

Since you cannot take the square root of a negative number to produce a real result, the only option that has two imaginary roots is D) -4, where the two imaginary roots are 2i and -2i.

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−7y−4x=1 ​7y−2x=53 Solve the system of equations​​
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konstantin123 [22]
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4 0
3 years ago
Read 2 more answers
Write an equation of the line that is parallel to the line whose equation is 3y+7=2x and passes through point (2,6).
Sladkaya [172]

Answer:

Step-by-step explanation:

To find the equation of a parallel line, we first need to find the slope of 3y + 7 = 2x.

We need to find it because, if two lines are parallel, then that means they have the same slope.

The best way to do this is solve for y:

3y+7=2x\\3y=2x-7\\y=\frac{2}{3}-\frac{7}{3}

Due to the rule that in y = mx + b, m = the slope, we find that the slope is 2/3.

Now we use that slope in the same formula to find b of the line we're trying to find the equation for, and then we'll have our answer. We find b by plugging in (2, 6) for x and y:

y = mx+b\\y=\frac{2}{3}x+b\\6=\frac{2}{3}(2)+b\\18=4+3b\\ 14=3b\\\frac{14}{3} = b

So our line is:

y=\frac{2}{3}x+\frac{14}{3}

5 0
3 years ago
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