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Alika [10]
2 years ago
15

a business want to increase its number of employees by 65% to 20,460. How many employees does the company currently have?

Mathematics
1 answer:
Crazy boy [7]2 years ago
5 0

Answer:

12,400

Step-by-step explanation:

Let the current employees be x

65% increase in number = 0.65x

If the total number of employees after the increase is 20,460, then;

x + 0.65x = 20,460

1.65x = 20,460

x = 20,460/1.65

x = 12,400

Hence the current number of employees is 12,400

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mina [271]

Answer:

A = 437 mm²

Step-by-step explanation:

The general formula for the area of a triangle:

A = \frac{1}{2}bh, where 'b' is the measure of the base and 'h' is the measure of the height

Given the dimensions of the triangle in the picture:

A = \frac{1}{2}(38)(23) = 437 mm²

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A square has four even sides and the perimeter is equal to the sum of all of the sides.
P=s+s+s+s=4s
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6 0
3 years ago
What is the value of d + e + f when d = 20, e = –4 and f = –2?
saw5 [17]
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2 years ago
ANSWER CHOICES LISTED!!!
Kipish [7]

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Step-by-step explanation:

8 0
2 years ago
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A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.
scZoUnD [109]

Answer: The required ratio will be

84:1034

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

2x=30\\\\x=\frac{30}{2}=15\ inches

So, Length of AD becomes

3x=3\times 15=45\ inches

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

\frac{30}{2}=15\ inches

So, Area of semicircle along AB and CD is given by

2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2

Radius of semicircle along AD is given by

\frac{45}{2}=22.5\ inches

Area of semicircle along AD and BC is given by

2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2

And the combined area of the semicircles is given by

\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2

Area of rectangle is given by

Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034

Hence, the required ratio will be

84:1034

8 0
2 years ago
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