Mid point of the points PQ is (₋0.3 , 3.25)
Given points are:
P(₋2 , 2.5)
Q(1.4 , 4)
midpoint of PQ = ?
A location in the middle of a line connecting two points is referred to as the midpoint. The midpoint of a line is located between the two reference points, which are its endpoints. The line that connects these two places is split in half equally at the halfway.
The midpoint calculation is the same as averaging two numbers. As a result, by adding any two integers together and dividing by two, you may find the midpoint between them.
Midpoint formula (x,y) = (x₁ ₊ x₂/2 , y₁ ₊ y₂/2)
we have two points:
P(₋2,2.5) = (x₁,y₁)
Q(1.4,4) = (x₂,y₂)
Midpoint = (₋2 ₊ 1.4/2 , 2.5₊4/2)
= (₋0.6/2 , 6.5/2)
= (₋0.3 , 3.25)
Hence we determined the midpoint of PQ as (₋0.3 , 3.25)
Learn more about coordinate geometry here:
brainly.com/question/7243416
#SPJ9
Answer:
b
Step-by-step explanation:
the hypotenuse is equal to the square root of 2 times x in a 45 45 90 right triangle
the square root of 2 times the square root of 2 cancels out to equal 2 and 2 times 3 is 6 so the hypotenuse equals 6
<span>1:4 is your ratio simplified.</span>
Answer:
x = 729/4 = 182.250
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that:
The numbers of the possible public swimming pools are 5
From past results, we have 0.007 probability of finding bacteria in a public swimming area.
In the public swimming pool, the probability of not finding bacteria = 1 - 0.007
= 0.993
Thus;
Probability of combined = Probability that at least one public
sample with bacteria swimming area have bacteria
Probability of combined sample with bacteria = 1 - P(none out of 5 has
bacteria)
Probability of combined sample with bacteria = 1 - (0.993)⁵
= 1 - 0.9655
= 0.0345
Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345
From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.
Thus, we can conclude that; Yes, the probability is low enough that there is a need for further testing.