Help me please thanks

Mathematics

2 answers:

Natalija [7]3 years ago

8 0

Answer:

B. 5/3

Step-by-step explanation:

You can find the correct answer to this problem by seeing if the answer choices fit the following criteria:

- It is greater than 1.5; the number line only provides intervals every .5 interval. The nearest interval below G is 1.5

- It is less than 2; the nearest interval above G is 2.

Now, let's look at the answers:

- 1.4; this answer won't work because 1.4 < 1.5

- 3/5; this answer won't work because it is also less than 1.5 (3/5 = .6 and .6 < 1.5)

- 5/3; this answer works because it is greater than 1.5. You can tell because it is equal to 1 2/3 and 2/3 is greater than 1/2or .5. 5/3 is also less than 2

- 2.6; this answer won't work because it is greater than 2

Anastasy [175]3 years ago

5 0

I’m going to say it 3/5 because the other answer are too large

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A random sample of 9 wheels of cheese yielded the following weights in pounds has a sample mean of 20.90 and a sample variance o

Ronch [10]

Answer:

$2.002 \leq \sigma^2 \leq 11.365$

Step-by-step explanation:

1) Data given and notation

s represent the sample standard deviation

$s^2$ represent the sample variance

n=9 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^9 (x_i -\bar x)^2}{n-1}}
The sample variance given was [tex]s^2=3.45$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.