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3 years ago

Plsssssssssssssssssssss

Mathematics

1 answer:

sladkih [1.3K]3 years ago

6 0

Answer: 100 ft^2

Step-by-step explanation:

Replace s with 5 in your equation and solve:

$4s^2$

$4(5)^2$

$4(25)$

= $100\\$

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4 years ago

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Express (16³) 1/4 in simplest radical form.

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2 years ago

Concert ticket sales of £21,000 are split in the ratio of 2 : 5 between the venue and the band.

ella [17]

Answer:

Step-by-step explanation:

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6 0

3 years ago

When records were first kept (t=0), the population of a rural town was 260 people. During the following years, the population gr

Firdavs [7]

Answer:

(a) The population after 15 years is 2678.

(b)Therefore the population P(t) at any time t>0 is

$P(t)= 45t+30 {t^{\frac32}}+260$

Step-by-step explanation:

Given that,

The population grew at a rate of

$P'(t)=45(1+\sqrt t)$

Integrating both sides

$\int P'(t) dt=\int 45(1+\sqrt t)dt$

$\Rightarrow \int P'(t) dt=\int (45+45\sqrt t)dt$

$\Rightarrow \int P'(t) dt=\int 45\ dt+\int 45\sqrt t\ dt$

$\Rightarrow P(t)= 45t+45\ \frac{t^{\frac12+1}}{\frac12+1}+c$ [ c is integration constant]

$\Rightarrow P(t)= 45t+45\ \frac{t^{\frac32}}{\frac32}+c$

$\Rightarrow P(t)= 45t+45\times\frac 23 \times {t^{\frac32}}+c$

$\Rightarrow P(t)= 45t+30 {t^{\frac32}}+c$

When t=0 , P(0)= 260

$\therefore 260= 45\times0+30\times {0^{\frac32}}+c$

$\Rightarrow c=260$

$\therefore P(t)= 45t+30 {t^{\frac32}}+260$

Therefore the population P(t) at any time t>0 is

$P(t)= 45t+30 {t^{\frac32}}+260$

To find the population after 15 years, we need to plug t=15 in the above expression.

$P(15)=( 45\times 15)+30( {15^{\frac32}})+260$

≈2678

The population after 15 years is 2678.

5 0

3 years ago

HELP PLEASE! (30 PTS)

kozerog [31]

Answer:

A because if you reflect over the x axis it’ll be flipped.

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3 years ago

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