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muminat
3 years ago
10

M/4 - 3 = 5 HELPPPPPPPPP PLZZZXZZZZZZZZZZZZZZZZZZ

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0
M-32 should be correct
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Answer:

b.21

Step-by-step explanation:

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What is the circumfrenice of a diamiter of 7 inches
KIM [24]

Answer:

22 in

Step-by-step explanation:

<u>circumference of a circle = 2 π r</u>

where radius (r) = 7/2 in. = 3.5 in

C = 2 π (3.5)

   = 22 in

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3 years ago
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Find the radius of a circle with a circumference of 69.1 yd
Arte-miy333 [17]

34.55 gcgbycfgycbnfuymiklbdxrdytjmu

4 0
3 years ago
Consider the expression 16y^2 . Select the correct statement:
tiny-mole [99]

Step-by-step explanation:

Given expression is:

16y^2

We will solve each statement one by one to see which statements are correct.

<u>If y=3/4, the values of 16y^2 is 12</u>

Putting y = 3/4 in expression

16y^2 = 16 *(\frac{3}{4})^2 = 16 * \frac{9}{16} = 9

<u>If y=1/4, the values of 16y^2 is 2</u>

Putting y = 1/4 in expression

<u></u>16y^2 = 16 *(\frac{1}{4})^2 = 16 * \frac{1}{16} = 1<u></u>

<u></u>

<u>If y=3/8, the values of 16y^2 is 4/9</u>

Putting y = 3/8 in expression

<u></u>16y^2 = 16 *(\frac{3}{8})^2 = 16 * \frac{9}{64} = \frac{9}{4}<u></u>

<u></u>

<u>If y=1/8, the values of 16y^2 is 1/4</u>

Putting y = 1/8 in expression

<u></u>16y^2 = 16 *(\frac{1}{8})^2 = 16 * \frac{1}{64} = \frac{1}{4}<u></u>

<u></u>

<u></u>

<u>If y=2/3, the values of 16y^2 is 3/4</u>

Putting y = 2/3 in expression

<u></u>16y^2 = 16 *(\frac{2}{3})^2 = 16 * \frac{4}{9} = \frac{64}{9}<u></u>

<u></u>

<u>Hence,</u>

The correct statement is:

If y=1/8, the values of 16y^2 is 1/4

Keywords: Expressions, variables

Learn more about expressions at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

7 0
3 years ago
Select the equation of the line that passes through the point (5, 7) and is perpendicular to the line x = 4.
tresset_1 [31]

Solution:

Equation of line perpendicular to , x=4 is

y +k=0

As, keep in mind , the equation of line perpendicular to , ax + by +c=0 is b x - a y +c=0

As, given the line perpendicular to, x =4, passes through the point (5,7).  

So, y+k =0, passes through (5,7).

→ 7 +k=0

→ k= -7

So, line perpendicular to x=4, which passes through the point (5,7) is →y-7=0 that is y=7.

Option (C) →y=7

7 0
3 years ago
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