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bagirrra123 [75]
3 years ago
14

1. Use a calculator to find all solutions in the interval (0, 2_). Round the answers to two decimal places. (Enter your answers

as a comma-separated list. If there is no solution, enter NO SOLUTION.)
sin x cos x = 0.027

2. Use a calculator to find all solutions in the interval (0, 2_). Round the answers to two decimal places. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)
cot x = _2.83
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0
1) we know that  sin2x=2sinxcosx, so sinxcosx=(1/2)sin2x, but sinxcosx=0.027
(1/2)sin2x=0.027, sin2x=0.054, arcsin(0.054)=2x, 3.09=2x, x=1.54 degree (x is in (0, 2), it is verified)


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(-19+7i)-(29+32i)=<br><br> in the form (a+bi)
olga_2 [115]
ANSWER

-48-25i

EXPLANATION

We want to simplify the expression,

(-19+7i) - (29+32i)

Let us expand the bracket to obtain,

-19+7i-29-32i

We now group the complex number parts and real number parts.

-19 -29+7i-32i


We simplify further to obtain,

- 48-25i


This is in the form,

a+bi

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bonufazy [111]
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Factor completely x^3 + 1/8
maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

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Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

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(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

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Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer:  ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0
3 years ago
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Make me Brilliant

Step-by-step explanation:

Make me Brilliant then you are legend

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