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stepan [7]
4 years ago
5

Which expressions are polynomials?

Mathematics
1 answer:
igor_vitrenko [27]4 years ago
6 0

Option A: z + 1

Option B: 6 + w

Option D: 2 x^{4}-y

Solution:

Let us first define the polynomial.

A polynomial can have constants, variables, exponents and fractional coefficients.

A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.

<u>To find which expressions are polynomial:</u>

Option A: z + 1

By the definition, z + 1 is a polynomial.

It is polynomial.

Option B: 6 + w

By the definition, 6 + w is a polynomial.

It is polynomial.

Option C: y^{2}-\sqrt[3]{y}+4

y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4

Here, y have fractional exponent.

So, it is not a polynomial.

Option D: 2 x^{4}-y

By the definition, 2 x^{4}-y is a polynomial.

It is polynomial.

Hence z + 1, 6 +w and 2 x^{4}-y are polynomials.

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Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0
Arada [10]

Answer:

b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0

Step-by-step explanation:

The given matrix addition is

B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

On equating both sides.

b_{11}+15=1\Rightarrow b_{11}=-14

b_{12}-7=2\Rightarrow b_{12}=9

b_{13}+4=12\Rightarrow b_{13}=8

b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

3 0
3 years ago
Luis distributes 49 roses equally among 7 friends. Then, 3 of his friends combine the roses they received to make a bouquet. How
antoniya [11.8K]

Answer:

21 roses

Step-by-step explanation:

49 / 7 = 7

Each friend got 7 roses.

7 x 3 = 21

3 friends combine their roses together, making a bouquet of 21 roses.

3 0
3 years ago
The location of the in center of abc is closest to:
MAVERICK [17]

Answer:

Point D

Step-by-step explanation:

5 0
2 years ago
If a² + b² = z and ab = y, which of the following is equivalent to 4z + 8y? Show all the steps.
Ivenika [448]

Answer:

The answer to your question is:       (2a + 2b)²

Step-by-step explanation:

a² + b² = z

ab = y

Which is equivalent to 4z + 8y ?

Substitution

                                     4(a² + b²) + 8(ab)

Simplify                        4a² + 4b² + 8ab

Order                            4a² + 8ab + 4b²       It's a perfect square trynomial

Factorize                     (2a + 2b)²

7 0
4 years ago
Read 2 more answers
A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
Over [174]

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

A survey of 35 people was conducted to compare their self-reported height to their actual height.

This means that n = 35

From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

t = 3.36

The test statistic is t = 3.36.

3 0
3 years ago
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