All categories

3 years ago

What is the value of the expression 2 + 4x (3 + 7) *

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

20=4x

Step-by-step explanation:

if finding x divide by 4 and x=5

You might be interested in

How do I turn 25/8 into a mixed number

vovikov84 [41]

You can turn 25/8 into a mixed number by dividing it. It would = 3

3 0

4 years ago

Two angles are supplementary. One angle measurement is 30 more than the other. What is the measure of the smaller angle?

Drupady [299]

60 because it has to equal at least 90 degrees

4 0

3 years ago

Write the square roots of 49 i in ascending order of the angle.

Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

$r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}} = \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )$

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°)) and 7·(cos(45°) + i·sin(45°))

8 0

3 years ago

HELP ASP ON KITCHEN MATH !!!

Komok [63]

Answer:

1 1/2 shortening

1 tsp salt

4 1/2 granulated sugar

1 or 3 tsp baking soda (not sure if it’s 1/2 or 1 1/2 for the original recipe)

1/2 eggs

4 c cake flour

1 vanilla extract

food coloring

1/2 butter flavoring

8 0

3 years ago

Read 2 more answers

Help plz find the equation

tatiyna

Question # 1

Step-by-step Explanation:

Given

$\frac{1}{2}\div \frac{2}{3}$

solving

$\frac{1}{2}\div \frac{2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{1}{2}\times \frac{3}{2}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{1\times \:3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:1\times \:3=3$

$=\frac{3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:2=4$

$=\frac{3}{4}$

Therefore, completing the blanks:

$\frac{1}{2}\div \frac{2}{3}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}$

Question # 3

Step-by-step Explanation:

Given

$\frac{2}{5}\div \frac{3}{4}$

solving

$\frac{2}{5}\div \frac{3}{4}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2}{5}\times \frac{4}{3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2\times \:4}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:4=8$

$=\frac{8}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15$

$=\frac{8}{15}$

Therefore, completing the blanks:

$\frac{2}{5}\div \frac{3}{4}=\frac{2}{5}\times \:\frac{4}{3}=\frac{8}{15}$

Question # 5

Step-by-step Explanation:

Given

$\frac{3}{4}\div \frac{5}{7}$

solving

$\frac{3}{4}\div \frac{5}{7}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{3}{4}\times \frac{7}{5}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{3\times \:7}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\times \:7=21$

$=\frac{21}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:4\times \:5=20$

$=\frac{21}{20}$

Therefore, completing the blanks:

$\frac{3}{4}\div \frac{5}{7}=\frac{3}{4}\times \:\frac{7}{5}=\frac{21}{20}$

6 0

3 years ago