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Vadim26 [7]
3 years ago
11

A projectile fired at 5 m/s from a gun. If the horizontal component of the initial velocity is equal to 4 m/s. What is the value

of the vertical component?
Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

the  \: value \:  of  \: the \:  vertical  \: component \to : \\  (v_v) = 3m {s}^{ - 1}  \\

Step-by-step explanation:

let \: the \: velocity \: be \to \: v \\let \: the \: horizontal \: component \: be \to \: v_h \\ let \: the \: vertical \: component \: be \to \: v_v \\ applying \: the \: pythagorean \: rule \: of \: vectors \to :  \\  {v}^{2}  =  {v_v}^{2}  +  {v_h}^{2}  \\  {v_v}^{2}  =  {v}^{2}  - {v_h}^{2}  \\ {v_v}^{2} = {5}^{2}  - {4}^{2}  \\ v_v =  \sqrt{(25 - 16)}  \\ v_v =  \sqrt{9}  \\ \boxed{ v_v = 3 {ms}^{ - 1} }

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