Plz help will mark brainly

Please help. Will be rewarded 20 points!

zalisa [80]

Answer:

$200

Step-by-step explanation:

2.5 % commission on sales

he sold 8000

his commission will be sales * 2.5%

commission = 8000 * .025

= 200

8 0

2 years ago

Read 2 more answers

Find the measure of line segment DF. A) 12 B) 13 C) 14 D) 15

brilliants [131]

As per the Intersecting Chords theorem, if two chords cross in a circle, the products of the chord segments' measures are equal. The measure of the line segment is DF is 14 units.

<h3>What is Intersecting Chords theorem?</h3>

If two chords cross in a circle, the products of the chord segments' measures are equal.

As per the Intersecting Chords theorem, the product of DF and FB will be equal to the product of CF and FA, therefore,

DF×FB = CF×FA

(x+8) × 8 = 16 × 7

(x+8) = (16×7)/8

(x+8) = 14

Hence, the measure of the line segment is DF is 14 units.

Learn more about Intersecting Chords theorem:

brainly.com/question/15298662

#SPJ1

4 0

2 years ago

If two points pass through each other it will be function or if it doesn't pass

Rasek [7]

Answer:

If two points pass through each other it means that it is not a function. The vertical line test shown proves that fact.

Step-by-step explanation:

5 0

2 years ago

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Gelneren [198K]

Answer:

(a) P (Z < 2.36) = 0.9909 (b) P (Z > 2.36) = 0.0091

(c) P (Z < -1.22) = 0.1112 (d) P (1.13 < Z > 3.35) = 0.1288

(e) P (-0.77< Z > -0.55) = 0.0705 (f) P (Z > 3) = 0.0014

(g) P (Z > -3.28) = 0.9995 (h) P (Z < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, $X \sim N (\mu, \sigma^{2})$ , then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean. The z-scores are standardized scores.

The distribution of these z-scores is known as the standard normal distribution.

(a)

Compute the value of P (Z < 2.36) as follows:

P (Z < 2.36) = 0.99086

≈ 0.9909

Thus, the value of P (Z < 2.36) is 0.9909.

(b)

Compute the value of P (Z > 2.36) as follows:

P (Z > 2.36) = 1 - P (Z < 2.36)

= 1 - 0.99086

= 0.00914

≈ 0.0091

Thus, the value of P (Z > 2.36) is 0.0091.

(c)

Compute the value of P (Z < -1.22) as follows:

P (Z < -1.22) = 0.11123

≈ 0.1112

Thus, the value of P (Z < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < Z > 3.35) as follows:

P (1.13 < Z > 3.35) = P (Z < 3.35) - P (Z < 1.13)

= 0.99960 - 0.87076

= 0.12884

≈ 0.1288

Thus, the value of P (1.13 < Z > 3.35) is 0.1288.

(e)

Compute the value of P (-0.77< Z > -0.55) as follows:

P (-0.77< Z > -0.55) = P (Z < -0.55) - P (Z < -0.77)

= 0.29116 - 0.22065

= 0.07051

≈ 0.0705

Thus, the value of P (-0.77< Z > -0.55) is 0.0705.

(f)

Compute the value of P (Z > 3) as follows:

P (Z > 3) = 1 - P (Z < 3)

= 1 - 0.99865

= 0.00135

≈ 0.0014

Thus, the value of P (Z > 3) is 0.0014.

(g)

Compute the value of P (Z > -3.28) as follows:

P (Z > -3.28) = P (Z < 3.28)

= 0.99948

≈ 0.9995

Thus, the value of P (Z > -3.28) is 0.9995.

(h)

Compute the value of P (Z < 4.98) as follows:

P (Z < 4.98) = 0.99999

≈ 0.9999

Thus, the value of P (Z < 4.98) is 0.9999.

**Use the z-table for the probabilities.

3 0

2 years ago

Solve each quadratic equation by factoring: NEED THIS ASAP WILL GIVE BRAINLIEST

Nadusha1986 [10]

Answer:

9) x = 6,4

10) R = -3,-4

Step-by-step explanation:

Hope this helps dude

6 0

2 years ago