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3 years ago

Cesar is 35 years old. He has $870 in a checking account, $2900 in a savings

Mathematics

2 answers:

Montano1993 [528]3 years ago

7 0

Answer:

the answer is a 3770.

Step-by-step explanation:

mamaluj [8]3 years ago

6 0

Answer:

A. $3770

Step-by-step explanation:

The correct answer must be $3770 (not $3270), checking accounts and savings accounts are liquid assets. However, cars are not liquid assets because liquid assets are things that can be quickly turned into cash without losing much if any of their inherent value. In this case, the retirement account is not a liquid asset as it is designed to hold your money until retirement age, and given that Cesar is 35 years old so he has not reached retirement age.

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2 years ago

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BlackZzzverrR [31]

Answer:

Step-by-step explanation:

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3 years ago

441 is 63% of what number

blagie [28]

Question: 441 is 63% of what number?
=> 63% = 63% / 100% = 0.63
Since 441 is the 63% let’s find the value of 37% to get the toal of 100%
Solution, follow the formula
=> 0.63x = 441 – where x will be the value of the missing 100% value.
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let’s check if we have the correct answer:
=> 700 * .63 = 441

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3 years ago

Divide (6-q+8q^3-4q^2)/(2q-2)

mestny [16]

Answer:

Step-by-step explanation:

4q2 + 2q + 3

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4 0

3 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of years that the time could be read at night is 30.4 years.

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3 years ago