OW has a radius of 10 mm

1 answer:

3 0

Answer: triangle inscribed in a semicircle is always a right triangle, triangle ABC is a right ... With that information, we can conclude that triangle ABC is a 6-8-10 right ... Since the diameter is 10, the radius is 5. ... I am now bumping it up - doing my job.

Step-by-step explanation:

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What are the solutions to 6x(second power 2)-5x-4=0

Alekssandra [29.7K]

6x²-5x-4=0
x=(-b+/√b²-4ac)/2a

D=b²-4ac=25+4*6*4=121, √D=√121=11
x=(5+/-11)/12
x1=-6/12=-1/2
x2=16/12=4/3

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The measurts of the angles of a triangle are shown in the figure below. Solve for x.<br> 33°<br> A

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Answer:

Step-by-step explanation:

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The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check

Verdich [7]

Answer:

$n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11$

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma =150$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

$\bar X = \frac{740+920}{2} = 830$

and the margin of error is given by :

$ME = \frac{920-740}{2}= 90$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got: