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3 years ago

Find the midpoint M of the line segment joining the points P= (-7,-8) and Q = (3,2)

Mathematics

1 answer:

Fed [463]3 years ago

3 0

Answer:

(-2, -3)

Step-by-step explanation:

To solve this problem, we use the midpoint formula.

M = $\frac{x1 + x2}{2} , \frac{y1+ y2}{2}$

Plug your coordinates in:

M = $\frac{-7 + 3}{2} , \frac{-8 + 2}{2}$

Simplify:

M = $\frac{-4}{2} , \frac{-6}{2}$

M = (-2,-3)

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: Which equations have an infinite number of solutions? Select all that apply. A -2(x - 2) + 3x = x - 4 B 2x + 4(x - 1) = 3(2x +

MissTica

Option C and Option D

3x + 2(x - 2) + 6 = 2(2x + 3) + x - 4 has infinite number of solutions

4(x + 2) + x + 1 = 2x - 3 + 3(x + 4) has infinite number of solutions

<h3><u>Solution:</u></h3>

Given that we have to find the equations that has infinite number of solutions

If we end up with the same term on both sides of the equal sign, such as 4 = 4 or 4x = 4x, then we have infinite solutions.

If we end up with different numbers on either side of the equal sign, as in 4 = 5, then we have no solutions.

<h3><u>Option A</u></h3>

-2(x - 2) + 3x = x - 4

Multiply the terms inside the bracket

-2x + 4 + 3x = x - 4

x + 4 = x - 4

Thus this equation does not have infinite number of solutions

<h3><u>Option B</u></h3>

2x + 4(x - 1) = 3(2x + 1) - 2(x - 1)

2x + 4x - 4 = 6x + 3 - 2x + 2

6x - 4 = 4x + 5

6x - 4x = 5 + 4

2x = 9

$x = \frac{9}{2}$

Thus this equation has only one solution.

Thus this equation does not have infinite number of solutions

<h3><u>Option C</u></h3>

3x + 2(x - 2) + 6 = 2(2x + 3) + x - 4

3x + 2x - 4 + 6 = 4x + 6 + x - 4

5x + 2 = 5x + 2

Thus this equation has infinite number of solutions

<h3><u>Option D</u></h3>

4(x + 2) + x + 1 = 2x - 3 + 3(x + 4)

4x + 8 + x + 1 = 2x - 3 + 3x + 12

5x + 9 = 5x + 9

Thus this equation has infinite number of solutions

3 0

4 years ago

What does x=_________

cluponka [151]

Answer:

x = 130˚

Step-by-step explanation:

x + 100˚ = 360˚

2 x = 360˚ - 100˚

2 x = 260˚

260˚ ÷ 2 = 130˚

5 0

3 years ago

Dont understand this can someone help me

natta225 [31]

$\bf \textit{when x = -2} \\\\\\ y=3x^2-x\implies y=3(-2)^2-(-2)\implies y=3(4)+2\implies y=14 \\\\\\ \textit{when x = 3} \\\\\\ y=3x^2-x\implies y=3(3)^2-(3)\implies y=3(9)-3\implies y=24 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{array}{l|llllllll} x&-3&-2&-1&0&1&2&3\\\\ y&30&\boxed{14}&4&0&2&10&\boxed{24} \end{array}$