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Masja [62]
3 years ago
13

Solve for x and show all your work 3x + 4 = 16

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
8 0

Answer:

x=4

Step-by-step explanation:

16-4=12

3x=12

3*4=12

Effectus [21]3 years ago
8 0

Answer: x=4

Step-by-step explanation:

You need to find the value of the variable "x".

To solve for "x", the first step is to apply the Subtraction property of equality, which states that:

If\ a=b\ then\ a-c=b-c

Then, you need to subtract 4 from both sides of the equation:

3x + 4 = 16\\3x + 4-4 = 16-4\\3x=12

And finally, you can apply the Division property of equality, which states that:

If\ a=b\ then\ \frac{a}{c}=\frac{b}{c}

Then you can divide both sides of the equation by 3, getting:

\frac{3x}{3}=\frac{12}{3}\\\\x=4

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Find the domain of the function. (enter your answer using interval notation.) f(x) = x + 4 x2 − 36
11111nata11111 [884]

Alright, lets get started.

The given function is :

f(x) = x + 4x^{2}  - 36

When we find the domain of any function, we consider the domian is set of input values for which function should remain real and defined.

In this given function , we have not given any points where function seems going undefined.

Hence the domain is : (-∞, +∞) : Answer

Hope it will help :)

8 0
3 years ago
What greatest three digit number whose hundreds is two less than its ones digit
kodGreya [7K]

Answer:

799

Step-by-step explanation:

Let x = the hundreds digit

Let y = the ones digit

x = y-2

We want to maximize x and y.  The both have to be single digit numbers

Rewriting this

x+2 =y

The largest x can be is 7 if y is a single digit

x is 7 and y is 9

We can pick the tens digit.  Make it as big as possible to make out number as large as possible

799

4 0
4 years ago
Which of these pairs of forces are acting on a stationary boat floating in calm water?
Lady bird [3.3K]

Answer:

A. Weight and buoyancy :P Have a good day

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help please please
hammer [34]

Answer:

A. The lines stay parallel

Step-by-step explanation:

Rigid transformations do not change angle or line relationships. When the parallel lines are rotated they stay parallel. Reflecting them will keep them parallel. If this were not true, then figured with parallel lines like rectangles and squares would change shape when reflected.

4 0
3 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
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