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mr_godi [17]
2 years ago
12

The diameter of a circle is 3 ft. Find its area to the nearest tenth.

Mathematics
1 answer:
tatiyna2 years ago
6 0

Answer:

A= 7.07ft squared

Step-by-step explanation:

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kotegsom [21]
2x+3x+x+9 = ??
5x+x+9 = ??
6x+9= ?? 
6x = -9   ---- subtract 9 on both sides

x = - 3/2  ----- didvide by 6 on both sides, simplify
5 0
2 years ago
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Evaluate.
tekilochka [14]

Step-by-step explanation:

W=-6, x=1.2, and z=-6/7

(W²x-3)÷10-z

we substitute

((-6²)(1.2)-3)÷10-(-6/7)

((-36)(1.2)-3) ÷10-(-6/7)

(-43.2-3) ÷10(6/7)

(-46.2)÷60/7

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-46.2*7/60

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8 0
2 years ago
35 = 1/2(x-5)(x-14) what does x equal?
Yanka [14]
The answer is x=19.
Hope it helps! (:
3 0
3 years ago
The area of a rectangular wall of a barn is 252 square feet. Its length is 10 feet longer than twice its width. Find the length
valentinak56 [21]

Answer: Length = 28 feet and width = 9 feet

Step-by-step explanation:

Let x = width of the wall.

Then, Length of the wall =  10+2x

Since , Area of rectangle = length x width

Then, as per given,

252= (10+2x)x\\\\\Rightarrow\ 252=10x+2x^2\\\\\Rightarrow\ 2x^2+10x-252=0\\\\\Rightarrow\ x^2+5x-126=0\\\\\Rightarrow\ x^2+14x-9x-126=0\\\\\Rightarrow\ (x+14)-9(x+14)=0\\\\\Rightarrow\ (x+14)(x-9)=0\\\\\Rightarrow\ x=-14 \ or \ x= 9

Since width cannot be negative , so x = 9

So width = 9 feet and length = 10+2(9)=10+18 = 28 feet

Hence, length is 28 feet and width is 9 feet of the wall of the barn.

7 0
3 years ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
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