Answer:
Error: Sariah treated every term as though it were an x-term. 5 and -4.5 are constants that cannot be combined with the x-terms. They can only be combined with each other.
Correct solution: 31x + 0.5
Strategy: Pay attention to the variables.
Step-by-step explanation:
In her first step, it appears Sariah added 13x and 5 to get 18x. These terms are not <em>like terms</em>, so cannot be added in this way. An appropriate strategy is to first identify all the terms with the same <em>variables</em> (x in this case), then add their <em>coefficients</em>.
... = x(13 +17 +1) +5 -4.5
Likewise, all the <em>constant</em> terms can be added.
... = 31x +(5 -4.5)
... = 31x + 0.5
Use the sum of cubes factoring rule
![a^3 + b^3 = (a+b)(a^2 - ab + b^2)](https://tex.z-dn.net/?f=a%5E3%20%2B%20b%5E3%20%3D%20%28a%2Bb%29%28a%5E2%20-%20ab%20%2B%20b%5E2%29)
to transform the left hand side into the right hand side.
![\frac { \sin^{3} \theta + \cos^{3} \theta } { \sin \theta + \cos \theta } = 1 - \sin \theta \cdot \cos \theta\\\\\frac { (\sin \theta + \cos \theta)(\sin^2 \theta - \sin \theta \cdot \cos\theta + \cos^2 \theta) } { \sin \theta + \cos \theta } = 1 - \sin \theta \cdot \cos \theta\\\\](https://tex.z-dn.net/?f=%5Cfrac%20%7B%20%5Csin%5E%7B3%7D%20%5Ctheta%20%2B%20%5Ccos%5E%7B3%7D%20%5Ctheta%20%7D%20%7B%20%5Csin%20%5Ctheta%20%2B%20%5Ccos%20%5Ctheta%20%7D%20%3D%201%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%20%5Ctheta%5C%5C%5C%5C%5Cfrac%20%7B%20%28%5Csin%20%5Ctheta%20%2B%20%5Ccos%20%5Ctheta%29%28%5Csin%5E2%20%5Ctheta%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%5Ctheta%20%2B%20%5Ccos%5E2%20%5Ctheta%29%20%7D%20%7B%20%5Csin%20%5Ctheta%20%2B%20%5Ccos%20%5Ctheta%20%7D%20%3D%201%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%20%5Ctheta%5C%5C%5C%5C)
![\sin^2 \theta - \sin \theta \cdot \cos\theta + \cos^2 \theta = 1 - \sin \theta \cdot \cos \theta\\\\(\sin^2 \theta + \cos^2\theta)- \sin \theta \cdot \cos\theta = 1 - \sin \theta \cdot \cos \theta\\\\1- \sin \theta \cdot \cos\theta = 1 - \sin \theta \cdot \cos \theta \ \ \checkmark\\\\](https://tex.z-dn.net/?f=%5Csin%5E2%20%5Ctheta%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%5Ctheta%20%2B%20%5Ccos%5E2%20%5Ctheta%20%3D%201%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%20%5Ctheta%5C%5C%5C%5C%28%5Csin%5E2%20%5Ctheta%20%2B%20%5Ccos%5E2%5Ctheta%29-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%5Ctheta%20%3D%201%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%20%5Ctheta%5C%5C%5C%5C1-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%5Ctheta%20%3D%201%20-%20%5Csin%20%5Ctheta%20%5Ccdot%20%5Ccos%20%5Ctheta%20%5C%20%5C%20%5Ccheckmark%5C%5C%5C%5C)
Throughout the entire process, the right hand side stayed the same.
On the last step, I used the pythagorean identity.
-3n=26
n=26/3
It is the fraction form.
Answer:
2
Step-by-step explanation:
We are given the distance QA=1.25 and QA'=2.5.
We make the relation 2.5/1.25=2 is the scale factor!
Answer:20.00
Step-by-step explanation: next time include the table but i managed to find it anyway