The concentration of A will be <em>0.34 mol·L⁻¹</em> after 60 min.
In a first-order reaction, the formula for the amount remaining after <em>n</em> half-lives is
![\text{[A]} = \frac{\text{[A]}_{0}}{2^{n}}\\](https://tex.z-dn.net/?f=%5Ctext%7B%5BA%5D%7D%20%3D%20%5Cfrac%7B%5Ctext%7B%5BA%5D%7D_%7B0%7D%7D%7B2%5E%7Bn%7D%7D%5C%5C)
If 
∴ ![\text{[A]} = \frac{\text{2.7 mol/L}}{2^{3.0}} = \frac{\text{2.7 mol/L}}{8.0} = \textbf{0.34 mol/L}](https://tex.z-dn.net/?f=%5Ctext%7B%5BA%5D%7D%20%3D%20%5Cfrac%7B%5Ctext%7B2.7%20mol%2FL%7D%7D%7B2%5E%7B3.0%7D%7D%20%3D%20%5Cfrac%7B%5Ctext%7B2.7%20mol%2FL%7D%7D%7B8.0%7D%20%3D%20%5Ctextbf%7B0.34%20mol%2FL%7D)
A catalyst
A catalyst can be in many forms
Answer:
26.8 °C
Explanation:
Step 1: Given and required data
- Energy transferred to the water (Q): 2100 J
- Initial temperature of the water (T₂): 23.6 °C
- Final temperature of the water (T₁): ?
- Specific heat of water (c): 4.184 J/g.°C
Step 2: Calculate the final temperature of the water
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C
The answer is -30 N
The explanation:
- to make the box move. so,the horizontal force must be greater than the frictional force.
-and when the horizontal force applied is 30 N. So, the box will remain stationary if the frictional force is equal in magnitude but opposite in direction to the horizontal force. means frictional force = -30 N
This is also being indicate that vertical force due to gravity is equivalent to the normal force when gravity force = 8 N and normal force =8 , meaning the box does not move vertically.
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Answer: 19.6%
Explanation: percent by mass =
100 × ((mass of solute (g)) ÷ (mass of solute + mass of solvent (g)))
100 × ((22.0gHCl) ÷ (22.0gHCl + 90.0gH20)) = 19.6%
