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3 years ago

Which of these is a mixture?? A.) salad B.) potassium C.) water D.) sugar

2 answers:

8 0

Salad would be a mixture because it is not chemically combined, if needed you could physically take it apart. So your answer would be A.)

vladimir2022 [97]3 years ago

5 0

The answer would be salad

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How many grams of CuF2 are needed to make a 2.8 M solution

11111nata11111 [884]

Molarity is given as,

Molarity = Moles / Volume of Solution ----- (1)

Also, Moles is given as,

Moles = Mass / M.mass

Substituting value of moles in eq. 1,

Molarity = Mass / M.mass × Volume

Solving for Mass,

Mass = Molarity × M.mass × Volume ---- (2)

Data Given;

Molarity = 2.8 mol.L⁻¹

M.mass = 101.5 g.mol⁻¹

Volume = 1 L (I have assumed it because it is not given)

Putting values in eq. 2,

Mass = 2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

Mass = 284.2 g of CuF₂

5 0

3 years ago

How many moles are in 43.5 g of sodium hydroxide (NaOH)?

Makovka662 [10]

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

3 0

2 years ago

Calculate the mass of butane needed to produce 96.7 g of carbon dioxide

ella [17]

31.9 grams butane needed to produce 96.7 grams CO2

5 0

2 years ago

What does each row (across) have in common?

Nastasia [14]

Row or periods have in common is the valence electron count. The valence electron count goes up as you move across the periodic table. Also atomic size gets smaller as you move from left to right

3 0

2 years ago

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular

mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

$\frac{actual yield}{theoretical yield} .100$

Where the actual yield is how much product was obtained, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is how much product could be obtained with the given reactants theoretically, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

$\frac{actual yield}{theoretical yield} .100$

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

5 0

2 years ago

Read 2 more answers