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3 years ago

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The formula P=a+b+c gives perimeter P of triangle side lengths a,b,and c how much greater is perimeter when triangle measures 33

yds 56yds and 65yds to a triangle that measures 26yds 49yds and 38yds

2 answers:

Tresset [83]3 years ago

7 0

Answer:

41 yds

Step-by-step explanation:

33+56+65=154

26+49+38=113

154-113=41 yds

seropon [69]3 years ago

3 0

Answer:

41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

First we have to calculate the perimeter of 1st triangle.

Given:

a = 33 yards

b = 56 yards

c = 65 yards

Now we have to calculate the perimeter of 2nd triangle.

Given:

a = 26 yards

b = 49 yards

c = 38 yards

Now we have to calculate which triangle has greater perimeter and how much greater.

Therefore, 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

Step-by-step explanation:

(154-113)

41 yards bigger

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What to pieces of information do you need to notify the equation of a line

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Answer:

The slope and the y-intercept when you’re in y-intercept form.

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What is the length of the arc if: 11. r=10 n=20 A15(pi)/ 7 B13(pi)/ 5 C16(pi)/ 2 D11(pi)/ 4 E 10(pi)/ 9 F 9(pi)/ 4 12. r=3 n=6 A

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Step-by-step explanation:

The formula for arc length [for the angle in degrees] is:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

here,

$n$ = degrees

$r$ = radius

using this we'll solve all the parts:

r = 10, n = 20:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (10) \left(\dfrac{20}{360}\right)$

from here, it is just simplification:

2 and 360 can be resolved: 360 divided by 2 = 180

$L = \pi (10) \left(\dfrac{20}{180}\right)$

10 and 180 can be resolved: 180 divided by 10 = 18

$L = \pi \left(\dfrac{20}{18}\right)$

finally, both 20 and 18 are multiples of 2 and can be resolved:

$L = \pi \left(\dfrac{10}{9}\right)$

$L = \dfrac{10\pi}{9}$ Option (E)

r=3, n=6:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (3) \left(\dfrac{6}{360}\right)$

$L = \dfrac{\pi}{10}$ Option (D)

r=4 n=7

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (4) \left(\dfrac{7}{360}\right)$

$L = \dfrac{7\pi}{45}$ Option (C)

r=2 n=x

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (2) \left(\dfrac{x}{360}\right)$

$L = \dfrac{x\pi}{90}$ Option (D)

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$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (y) \left(\dfrac{x}{360}\right)$

$L = \dfrac{xy\pi}{180}$ Option (E)

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3 years ago

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neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

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Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

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Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

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Answer:

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Hope this helps.

Step-by-step explanation:

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