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Klio2033 [76]
3 years ago
12

Find the distance between the points (-6, -8) and (0, -10).

Mathematics
1 answer:
inn [45]3 years ago
5 0

Answer:

2√10

Step-by-step explanation:

-√(x2-x1) squared +(y2-y1) squared

-√(0-(-6)) squared +(-10-(-8)) squared

- simplify and get 2√10 which you can simply further to 6,32( rounded off to two decimal places)

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How would you translate this situation below into an algebraic expression?
Natasha2012 [34]
Dime value: $0.10
Nickel value: $0.05

For this word problem, you are asked to create an algebraic expression (an equation) for the unknown variables. 

Now, we know that a dime is worth $0.10 or 10 cents and a nickel is worth $0.05 or 5 cents. So, all you would have to do is create an equation that takes those values into account. 
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Your algebraic expression would be B. 5n + 10d

I hope this helps!
5 0
3 years ago
A polygon is shown:
Klio2033 [76]

Answer:

My brain just exploded. I tried imagining what the shape would look like, and that didn't work. Also, I tried drawing the shape and that didn't work. I have no idea what the shape looks like. If you still need help with this question, maybe you can repost it with an image attached so we can know what the shape looks like.

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faust18 [17]

Answer:

I thinks it is -11

Step-by-step explanation:

3 0
3 years ago
How do you solve this?
Katarina [22]

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] ~\dotfill\\\\ (x-6)^2+(y+5)^2=16\implies [x-\stackrel{h}{6}]^2+[y-(\stackrel{k}{-5})]^2=\stackrel{r}{4^2}~\hfill \begin{cases} \stackrel{center}{(6,-5)}\\ \stackrel{radius}{4} \end{cases}

Check the picture below.

6 0
3 years ago
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I'm assuming that subtraction sign is mean to be an equals sign. If that is true than the answer is 403.75. 
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