A proof of the Alternate Interior Angles Theorem, using parallel lines a and b with transversal m, is shown below.
2 answers:
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(I)1.272727... = 14/11
(II)0.1282828...= 127/990
(The solution is in the picture
NB : the two points on the two numbers in the solution means those two numbers are recurring or repeating )
(II)0.1282828...= 127/990
(The solution is in the picture
NB : the two points on the two numbers in the solution means those two numbers are recurring or repeating )