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3 years ago

Write -12/15 as a decimal

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

4 0

Answer:

-0.8

Step-by-step explanation:

alukav5142 [94]3 years ago

3 0

Answer:

12.15

Step-by-step explanation:

you just put the decimal between the two number it cant be higher than the other

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Gina's number is 2 more than sara's. the sum of their numbers is 68. what are their numbers?

ikadub [295]

In order to solve this problem, we transform the statements into algebraic expressions. First, we assign the variables.

Let:

x = Gina’s number

y = Sara’s number

For the first equation, we show that Gina’s number is greater than Sara’s number by 2. For the second equation, we show that the sum of both numbers is 68.

(1) x – y = 2

(2) x + y = 68

We add the two expressions, which result in the expression: 2x = 70. Then we divide 70 by 2 to get the value of x. We then have x = 35. Using the second equation, we solve for y = 68-35. This gives y = 33. To summarize, Gina’s number is 35 while Sara’s number is 33.

8 0

3 years ago

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How much do i need to get to 500 so rite now I have 423 and I need 500

Elza [17]

Answer:

Step-by-step explanation:

just do 500-423

4 0

3 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

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3 years ago

Evaluate 4y-3 for y=1

Neko [114]

Answer:

Step-by-step explanation:

4(1)-3=?

4-3=1

8 0

4 years ago

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Please help. Is algebra. PLEASE HELP NO LINKS OR FILES. I don't want links.

Andru [333]

Answer:

Step-by-step explanation:

first, group the terms with the same power together and it would become (-9n⁵-4n⁵)+(n³-9n³)+(11n+6n). then, combine the terms in each group together which would get -13n⁵-8n³+17n as the answer

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3 years ago