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Artyom0805 [142]
3 years ago
9

We're doing math practice what's the answer

Mathematics
1 answer:
cluponka [151]3 years ago
3 0
Multiply 36 by 75 because they need to find how many yards they need
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The coordinates of triangle DEF are D(4,2)​, E(7,2)​, and F(6,8). If you translate triangle DEF 4 units right and 3 units down​,
rosijanka [135]

Answer:

E’ is (11,-1)

Step-by-step explanation:

Here, we want to get the new coordinates of E

The translation is 4 units right ( add 4 to x-value) and 3 units down ( subtract 3 from y-value)

So for E, we have

(7 + 4, 2-3)

= (11, -1)

4 0
2 years ago
G = cst (solve for s)
Harrizon [31]

Step-by-step explanation:

Simplifying

g = cst

Solving

g = cst

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Simplifying

g = cst

7 0
2 years ago
What is 1 +1 pls HELP
ElenaW [278]

Answer:

2

Step-by-step explanation:

Subject: Re: Need the math proof for 1 + 1 = 2

The proof starts from the Peano Postulates, which define the natural

numbers N. N is the smallest set satisfying these postulates:

P1. 1 is in N.

P2. If x is in N, then its "successor" x' is in N.

P3. There is no x such that x' = 1.

P4. If x isn't 1, then there is a y in N such that y' = x.

P5. If S is a subset of N, 1 is in S, and the implication

(x in S => x' in S) holds, then S = N.

Then you have to define addition recursively:

Def: Let a and b be in N. If b = 1, then define a + b = a'

(using P1 and P2). If b isn't 1, then let c' = b, with c in N

(using P4), and define a + b = (a + c)'.

Then you have to define 2:

Def: 2 = 1'

2 is in N by P1, P2, and the definition of 2.

Theorem: 1 + 1 = 2

Proof: Use the first part of the definition of + with a = b = 1.

Then 1 + 1 = 1' = 2 Q.E.D.

Note: There is an alternate formulation of the Peano Postulates which

replaces 1 with 0 in P1, P3, P4, and P5. Then you have to change the

definition of addition to this:

Def: Let a and b be in N. If b = 0, then define a + b = a.

If b isn't 0, then let c' = b, with c in N, and define

a + b = (a + c)'.

You also have to define 1 = 0', and 2 = 1'. Then the proof of the

Theorem above is a little different:

Proof: Use the second part of the definition of + first:

1 + 1 = (1 + 0)'

Now use the first part of the definition of + on the sum in

parentheses: 1 + 1 = (1)' = 1' = 2 Q.E.D.

3 0
3 years ago
Sorry to the people who were helping me earlier, but I actually don't get this one. I really need help if anyone could help with
Fed [463]
7/12
12/7
1`2/7
7/12 

a reciprocal you just flip the fraction 
5 0
3 years ago
Read 2 more answers
Please Help 30 Points
Virty [35]

Answer:

Step-by-step explanation:

5 0
2 years ago
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