If a student rides her skateboard on a straight road and does not speed up or slow down, she is traveling with a -

At room temperature, all samples of liquid water must have the same

laiz [17]

Density. water's density is always 1 g/ cm^3

4 0

3 years ago

Read 2 more answers

How many bonding and non bonding domains are on the central atom in NH2-

siniylev [52]

1bonding and 3non-bonding

(Refer to the attachment for structure

8 0

3 years ago

Read 2 more answers

What is the molality of ethylene glycol, c2h4(oh)2, in a solution prepared from 2. 331×103 g of ethylene glycol and 2. 00×103 g

qaws [65]

Molality of ethylene glycol, C₂H₄(OH)₂, in a solution prepared from 2. 331×10³ g of ethylene glycol and 2.00×10³ g of water, H₂O is 47.6m

Ethylene Glycol is known as C₂H₄(OH)₂. It is added in water to prepare an Antifreeze solution.

Given,

Mass of Ethylene Glycol = 2.331 × 10³ g = 2.331kg

Mass of Water = 2.00 × 10³ g

Since, Ethylene Glycol is in excess. Hence, it acts as a solvent and water acts as a solute.

We know, Molar Mass of Water = 18g

Hence, Moles of Water = Given mass of water / Molar Mass of Water

⇒ Moles of Water = 2000 / 18

⇒ Moles of Water = 111.1

Molality is defined as the moles of solute present in a given solvent in kg.

∴ Molality = Moles of Solute / Mass of Solvent (in kg)

Molality = Moles of Water / Mass of Ethylene Glycol

⇒ Molality = 111.1 / 2.331

⇒ Molality = 47.6m

Molality of ethylene glycol, C₂H₄(OH)₂, in a solution prepared from 2. 331×10³ g of ethylene glycol and 2.00×10³ g of water, H₂O is 47.6m

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3 0

2 years ago

Oxalic acid, H2C2O4, reacts

Dominik [7]

Answer:0.005M

Explanation:

First deduce the oxidation and reduction half equations and from that obtain the balanced redox reaction equation. From that, the number of moles of reacting species are seen from the stoichiometry of the reaction from which the number of moles of oxalate is obtained and substituted to obtain the molar concentration of oxalate.

6 0

4 years ago

You have cyclohexene, water, cyclohexanol, and a little sulfuric acid catalyst in a test tube at 60 oC and everything is at equi

Anvisha [2.4K]

Answer:

See explanation

Explanation:

We can convert cyclohexanol to cyclohexene in the presence of a strong acid such as sulfuric acid catalyst in a test tube at 60 oC by heating up the mixture to about 80 oC. This is a dehydration reaction so water is removed to yield the alkene. A drying agent is used to remove any trace amount of water left in the system. This overall reaction is endothermic.

Also, the reverse is the case when we want to carry out the hydration of cyclohexene to yield cyclohexanol. The overall reaction is exothermic and involves the addition of more water to the alkene and then cooling down the system to about 40 oC.

8 0

3 years ago