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Rainbow [258]
3 years ago
11

Jake hangs two balloons from a desk so that they are close together but not touching. Jake rubs one balloon with a wool cloth. H

e does nothing to the other balloon. What happens when he lets go of the balloons?
Cecilia is combing her hair. What will most likely happen when she holds the comb near a small, uncharged object


Wanda rubs a balloon against her wool sweater, and the balloon sticks to the sweater. Then she observes the balloon sticking to a wall. Why is this a scientific investigation but not an experiment?
Chemistry
2 answers:
Zepler [3.9K]3 years ago
4 0

Answer:Jake's balloon will stick together because the balloon he rubbed with wool became a temporary magnet. Knowing that positive pole of a magnet attracts negative pole of the magnet.

The object will stick to Cecilia's comb because of the phenomenon called magnetism.

Wanda has not identified any variable for his testing and have not established a controlled testing situation.

Explanation: Cecila's comb became charged from the constant combing and became a magnet.

Wanda has not set up a proper scientific experiment to define parameters for his testings.

kari74 [83]3 years ago
3 0
The objects that are rubbed together will create charges among themselves due to friction. 
(1) The balloon rubbed with a wool cloth will be charged. 
(2) If she comb near a small, uncharged object nothing will change. 
(3) This is a scientific investigation because it does not involved a step by step process to answer a scientific query. 
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Part A
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Answer:

ΔG° = -5.4 kJ/mol

ΔG = 873.2 J/mol = 0.873 kJ /mol

Explanation:

Step 1: Data given

ΔG (NO2) = 51.84 kJ/mol

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Step 2:

ΔG = ΔG° + RT ln Q

⇒with Q = the reaction quatient

⇒with T = the temperature = 298 K

⇒with R = 8.314 J / mol*K

⇒with ΔG° = ΔG° (N2O4) - 2*ΔG°(NO2 )

⇒ ΔG° = 98.28 kJ/mol - 2* 51.84  kJ/mol

⇒ ΔG° = -5.4 kJ/mol

Part B

ΔG =  ΔG° =RT ln Q

⇒with G° = -5.4 kj/mol = -5400 j/mol

⇒ with R = 8.314 J/K*mol

⇒with T = 298 K

⇒with Q = p(N2O4)/ [ p(NO2) ]² = 1.63/0.36² = 12.577

ΔG = -5400 + 8.314 * 298 * ln(12.577)

ΔG = -5400 + 8.314 * 298 * 2.532

ΔG = 873.2 J/mol = 0.873 kJ/mol

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