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lakkis [162]
3 years ago
13

Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 2x - 5y = 13 \\\\ -3x + 2y = 13 \

end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 2x−5y=13 −3x+2y=13 ​
Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer and Step-by-step explanation:

Given the system of equations:

2x – 5y = 13

–3x + 2y = 13

We can decide to eliminate either x or y in order to solve the simultaneous equations.

1. To eliminate x:

Multiply the first equation by the coefficient of x in the second equation and multiply the second equation by the coefficient of x in the first equation. By doing this the coefficients of x in the equations would be the same and subtracting them to be equal to zero becomes easy, thus eliminating that variable.

The coefficient of x in the second equation is –3, if we multiply the first equation by it we have:

–6x+15y = –39

The coefficient of x in the first equation is 2, if we multiply the second equation by it we have:

–6x+4y = 26

Subtracting the resulting equations we have:

11y = –65 and x is eliminated.

2. To eliminate y:

Multiply the first equation by the coefficient of y in the second equation and multiply the second equation by the coefficient of y in the first equation. By doing this the coefficients of y in the equations would be the same and subtracting them to be equal to zero becomes easy, thus eliminating that variable.

The coefficient of y in the second equation is 2, if we multiply the first equation by it we have:

4x–10y = 26

The coefficient of y in the first equation is –5, if we multiply the second equation by it we have:

15x–10y = –65

Subtracting the resulting equations we have:

–11x = 91 and y is eliminated.

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A line passes through the points (-6, 4) and (-2, 2). Which is the equation of the line?
cupoosta [38]

Answer:

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Step-by-step explanation:

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Being m the slope and b the y-intercept.

Assume we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

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\displaystyle m=\frac{2-4}{-2+6}=\frac{-2}{4}=-\frac{1}{2}

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