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nlexa [21]
3 years ago
11

A line passes through the points (-6, 4) and (-2, 2). Which is the equation of the line?

Mathematics
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

\displaystyle y=-\frac{1}{2}x+1

Step-by-step explanation:

The equation of any line in slope-intercept form is:

y=mx+b

Being m the slope and b the y-intercept.

Assume we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Two points are given: (-6,4) and (-2,2). Calculating the slope:

\displaystyle m=\frac{2-4}{-2+6}=\frac{-2}{4}=-\frac{1}{2}

The equation of the line is, so far:

\displaystyle y=-\frac{1}{2}x+b

To calculate the value of b, we use any of the given points, for example (-6,4):

\displaystyle 4=-\frac{1}{2}(-6)+b

\displaystyle 4=3+b

Solving:

b = 1

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{2}x+1}

We can see none of the choices is correct.

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